1
JEE Main 2024 (Online) 27th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Position of an ant ($$\mathrm{S}$$ in metres) moving in $$\mathrm{Y}$$-$$\mathrm{Z}$$ plane is given by $$S=2 t^2 \hat{j}+5 \hat{k}$$ (where $$t$$ is in second). The magnitude and direction of velocity of the ant at $$\mathrm{t}=1 \mathrm{~s}$$ will be :

A
$$16 \mathrm{~m} / \mathrm{s}$$ in $$y$$-direction
B
$$4 \mathrm{~m} / \mathrm{s}$$ in $$x$$-direction
C
$$9 \mathrm{~m} / \mathrm{s}$$ in $$\mathrm{z}$$-direction
D
$$4 \mathrm{~m} / \mathrm{s}$$ in $$y$$-direction
2
JEE Main 2023 (Online) 15th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
The position of a particle related to time is given by $x=\left(5 t^{2}-4 t+5\right) \mathrm{m}$. The magnitude of velocity of the particle at $t=2 s$ will be :
A
$14 \mathrm{~ms}^{-1}$
B
$16 \mathrm{~ms}^{-1}$
C
$10 \mathrm{~ms}^{-1}$
D
$06 \mathrm{~ms}^{-1}$
3
JEE Main 2023 (Online) 13th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The distance travelled by an object in time $$t$$ is given by $$s=(2.5) t^{2}$$. The instantaneous speed of the object at $$\mathrm{t}=5 \mathrm{~s}$$ will be:

A
$$5 \mathrm{~ms}^{-1}$$
B
$$12.5 \mathrm{~ms}^{-1}$$
C
$$62.5 \mathrm{~ms}^{-1}$$
D
$$25 \mathrm{~ms}^{-1}$$
4
JEE Main 2023 (Online) 13th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A passenger sitting in a train A moving at $$90 \mathrm{~km} / \mathrm{h}$$ observes another train $$\mathrm{B}$$ moving in the opposite direction for $$8 \mathrm{~s}$$. If the velocity of the train B is $$54 \mathrm{~km} / \mathrm{h}$$, then length of train B is:

A
80 m
B
200 m
C
120 m
D
320 m
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