1
JEE Main 2023 (Online) 11th April Evening Shift
+4
-1 A projectile is projected at $$30^{\circ}$$ from horizontal with initial velocity $$40 \mathrm{~ms}^{-1}$$. The velocity of the projectile at $$\mathrm{t}=2 \mathrm{~s}$$ from the start will be : (Given $$g=10 \mathrm{~m} / \mathrm{s}^{2}$$ )

A
$$20 \sqrt{3} \mathrm{~ms}^{-1}$$
B
Zero
C
$$20 \mathrm{~ms}^{-1}$$
D
$$40 \sqrt{3} \mathrm{~ms}^{-1}$$
2
JEE Main 2023 (Online) 11th April Morning Shift
+4
-1 From the $$\mathrm{v}-t$$ graph shown, the ratio of distance to displacement in $$25 \mathrm{~s}$$ of motion is: A
1
B
$$\frac{3}{5}$$
C
$$\frac{1}{2}$$
D
$$\frac{5}{3}$$
3
JEE Main 2023 (Online) 10th April Evening Shift
+4
-1 A person travels $$x$$ distance with velocity $$v_{1}$$ and then $$x$$ distance with velocity $$v_{2}$$ in the same direction. The average velocity of the person is $$\mathrm{v}$$, then the relation between $$v, v_{1}$$ and $$v_{2}$$ will be.

A
$$\mathbf{V}=\mathbf{V}_{1}+\mathbf{V}_{2}$$
B
$$V=\frac{v_{1}+V_{2}}{2}$$
C
$$\frac{1}{\mathrm{v}}=\frac{1}{\mathrm{v}_{1}}+\frac{1}{\mathrm{v}_{2}}$$
D
$$\frac{2}{\mathrm{~V}}=\frac{1}{\mathrm{v}_{1}}+\frac{1}{\mathrm{v}_{2}}$$
4
JEE Main 2023 (Online) 10th April Evening Shift
+4
-1 Two projectiles are projected at $$30^{\circ}$$ and $$60^{\circ}$$ with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:

A
$$1: \sqrt{3}$$
B
$$\sqrt{3}: 1$$
C
1 : 3
D
$$2: \sqrt{3}$$
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