1
JEE Main 2023 (Online) 11th April Evening Shift
+4
-1

A projectile is projected at $$30^{\circ}$$ from horizontal with initial velocity $$40 \mathrm{~ms}^{-1}$$. The velocity of the projectile at $$\mathrm{t}=2 \mathrm{~s}$$ from the start will be : (Given $$g=10 \mathrm{~m} / \mathrm{s}^{2}$$ )

A
$$20 \sqrt{3} \mathrm{~ms}^{-1}$$
B
Zero
C
$$20 \mathrm{~ms}^{-1}$$
D
$$40 \sqrt{3} \mathrm{~ms}^{-1}$$
2
JEE Main 2023 (Online) 10th April Evening Shift
+4
-1

Two projectiles are projected at $$30^{\circ}$$ and $$60^{\circ}$$ with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:

A
$$1: \sqrt{3}$$
B
$$\sqrt{3}: 1$$
C
1 : 3
D
$$2: \sqrt{3}$$
3
JEE Main 2023 (Online) 10th April Morning Shift
+4
-1

The range of the projectile projected at an angle of 15$$^\circ$$ with horizontal is 50 m. If the projectile is projected with same velocity at an angle of 45$$^\circ$$ with horizontal, then its range will be

A
50$$\sqrt2$$ m
B
100 m
C
100$$\sqrt2$$ m
D
50 m
4
JEE Main 2023 (Online) 8th April Evening Shift
+4
-1

The trajectory of projectile, projected from the ground is given by $$y=x-\frac{x^{2}}{20}$$. Where $$x$$ and $$y$$ are measured in meter. The maximum height attained by the projectile will be.

A
10 m
B
5 m
C
200 m
D
10$$\sqrt2$$ m
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