1
JEE Main 2020 (Online) 9th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A particle starts from the origin at t = 0 with an
initial velocity of 3.0 $$\widehat i$$ m/s and moves in the
x-y plane with a constant acceleration $$\left( {6\widehat i + 4\widehat j} \right)$$ m/s2 . The x-coordinate of the particle at the instant when its y-coordinate is 32 m is D meters. The value of D is :-
A
40
B
32
C
50
D
60
2
JEE Main 2020 (Online) 8th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A particle moves such that its position vector $$\overrightarrow r \left( t \right) = \cos \omega t\widehat i + \sin \omega t\widehat j$$ where $$\omega $$ is a constant and t is time. Then which of the following statements is true for the velocity $$\overrightarrow v \left( t \right)$$ and acceleration $$\overrightarrow a \left( t \right)$$ of the particle :
A
$$\overrightarrow v $$ and $$\overrightarrow a $$ both are perpendicular to $$\overrightarrow r $$
B
$$\overrightarrow v $$ and $$\overrightarrow a $$ both are parallel to $$\overrightarrow r $$
C
$$\overrightarrow v $$ is perpendicular to $$\overrightarrow r $$ and $$\overrightarrow a $$ is directed towards the origin
D
$$\overrightarrow v $$ is perpendicular to $$\overrightarrow r $$ and $$\overrightarrow a $$ is directed away from the origin
3
JEE Main 2019 (Online) 12th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A particle is moving with speed v = b$$\sqrt x $$ along positive x-axis. Calculate the speed of the particle at time t = $$\tau $$(assume that the particle is at origin t = 0)
A
$${{{b^2}\tau } \over {\sqrt 2 }}$$
B
$${{b^2}\tau }$$
C
$${{{b^2}\tau } \over 2}$$
D
$${{{b^2}\tau } \over 4}$$
4
JEE Main 2019 (Online) 12th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Two particles are projected from the same point with the same speed u such that they have the same range R, but different maximum heights, h1 and h2. Which of the following is correct ?
A
R2 = h1h2
B
R2 = 16 h1h2
C
R2 = 4 h1h2
D
R2 = 2h1h2
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