JEE Main 2022 (Online) 24th June Morning Shift | Motion in a Plane Question 49 | Physics

JEE Main 2022 (Online) 24th June Morning Shift

MCQ (Single Correct Answer)

-1

A projectile is projected with velocity of 25 m/s at an angle $$\theta$$ with the horizontal. After t seconds its inclination with horizontal becomes zero. If R represents horizontal range of the projectile, the value of $$\theta$$ will be :

[use g = 10 m/s²]

$${1 \over 2}{\sin ^{ - 1}}\left( {{{5{t^2}} \over {4R}}} \right)$$

$${1 \over 2}{\sin ^{ - 1}}\left( {{{4R} \over {5{t^2}}}} \right)$$

$${\tan ^{ - 1}}\left( {{{4{t^2}} \over {5R}}} \right)$$

$${\cot ^{ - 1}}\left( {{R \over {20{t^2}}}} \right)$$

JEE Main 2021 (Online) 1st September Evening Shift

MCQ (Single Correct Answer)

-1

The ranges and heights for two projectiles projected with the same initial velocity at angles 42$$^\circ$$ and 48$$^\circ$$ with the horizontal are R₁, R₂ and H₁, H₂ respectively. Choose the correct option :

R₁ > R₂ and H₁ = H₂

R₁ = R₂ and H₁ < H₂

R₁ < R₂ and H₁ < H₂

R₁ = R₂ and H₁ = H₂

JEE Main 2021 (Online) 31st August Morning Shift

MCQ (Single Correct Answer)

-1

A helicopter is flying horizontally with a speed 'v' at an altitude 'h' has to drop a food packet for a man on the ground. What is the distance of helicopter from the man when the food packet is dropped?

$$\sqrt {{{2gh{v^2} + 1} \over {{h^2}}}} $$

$$\sqrt {2gh{v^2} + {h^2}} $$

$$\sqrt {{{2{v^2}h} \over g} + {h^2}} $$

$$\sqrt {{{2gh} \over {{v^2}}} + {h^2}} $$

JEE Main 2021 (Online) 27th August Evening Shift

MCQ (Single Correct Answer)

-1

A player kicks a football with an initial speed of 25 ms^$$-$$1 at an angle of 45$$^\circ$$ from the ground. What are the maximum height and the time taken by the football to reach at the highest point during motion ? (Take g = 10 ms^$$-$$2)

h_max = 10 m

T = 2.5 s

h_max = 15.625 m

T = 3.54 s

h_max = 15.625 m

T = 1.77 s

h_max = 3.54 m

T = 0.125 s

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