JEE Main 2021 (Online) 26th August Evening Shift | Motion in a Plane Question 41 | Physics

JEE Main 2021 (Online) 26th August Evening Shift

MCQ (Single Correct Answer)

-1

A bomb is dropped by fighter plane flying horizontally. To an observer sitting in the plane, the trajectory of the bomb is a :

hyperbola

parabola in the direction of motion of plane

straight line vertically down the plane

parabola in a direction opposite to the motion of plane

JEE Main 2021 (Online) 20th July Morning Shift

MCQ (Single Correct Answer)

-1

A butterfly is flying with a velocity $$4\sqrt 2 $$ m/s in North-East direction. Wind is slowly blowing at 1 m/s from North to South. The resultant displacement of the butterfly in 3 seconds is :

$$12\sqrt 2 $$ m

20 m

3 m

15 m

JEE Main 2021 (Online) 16th March Evening Shift

MCQ (Single Correct Answer)

-1

A mosquito is moving with a velocity $$\overrightarrow v = 0.5{t^2}\widehat i + 3t\widehat j + 9\widehat k$$ m/s and accelerating in uniform conditions. What will be the direction of mosquito after 2 s?

$${\tan ^{ - 1}}\left( {{\sqrt {85} } \over 6}\right)$$ from y-axis

$${\tan ^{ - 1}}\left( {{5 \over 2}} \right)$$ from y-axis

$${\tan ^{ - 1}}\left( {{2 \over 3}} \right)$$ from x-axis

$${\tan ^{ - 1}}\left( {{5 \over 2}} \right)$$ from x-axis

JEE Main 2021 (Online) 26th February Evening Shift

MCQ (Single Correct Answer)

-1

The trajectory of a projectile in a vertical plane is y = $$\alpha$$x $$-$$ $$\beta$$x², where $$\alpha$$ and $$\beta$$ are constants and x & y are respectively the horizontal and vertical distances of the projectile from the point of projection. The angle of projection $$\theta$$ and the maximum height attained H are respectively given by :

$${\tan ^{ - 1}}\alpha ,{{{\alpha ^2}} \over {4\beta }}$$

$${\tan ^{ - 1}}\alpha ,{{4{\alpha ^2}} \over \beta }$$

$${\tan ^{ - 1}}\left( {{\beta \over \alpha }} \right),{{{\alpha ^2}} \over \beta }$$

$${\tan ^{ - 1}}\beta ,{{{\alpha ^2}} \over {2\beta }}$$

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