AIEEE 2012 | Motion Question 159 | Physics

An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by :
$${{dv} \over {dt}} = - 2.5\sqrt v $$ where v is the instantaneous speed. The time taken by the object, to come to rest, would be :

2 s

4 s

8 s

1 s

AIEEE 2011

MCQ (Single Correct Answer)

-1

A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountain is v, the total area around the fountain that gets wet is :

$$\pi {{{v^4}} \over {{g^2}}}$$

$${\pi \over 2}{{{v^4}} \over {{g^2}}}$$

$$\pi {{{v^2}} \over {{g^2}}}$$

$$\pi {{{v^2}} \over g}$$

AIEEE 2010

MCQ (Single Correct Answer)

-1

A particle is moving with velocity $$\overrightarrow v = k\left( {y\widehat i + x\widehat j} \right)$$, where K is a constant. The general equation for its path is

y = x² + constant

y² = x + constant

xy = constant

y² = x² + constant

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