JEE Main 2021 (Online) 27th July Evening Shift | Geometrical Optics Question 170 | Physics

A prism of refractive index $$\mu$$ and angle of prism A is placed in the position of minimum angle of deviation. If minimum angle of deviation is also A, then in terms of refractive index

$$2{\cos ^{ - 1}}\left( {{\mu \over 2}} \right)$$

$${\sin ^{ - 1}}\left( {{\mu \over 2}} \right)$$

$${\sin ^{ - 1}}\left( {\sqrt {{{\mu - 1} \over 2}} } \right)$$

$${\cos ^{ - 1}}\left( {{\mu \over 2}} \right)$$

JEE Main 2021 (Online) 25th July Evening Shift

MCQ (Single Correct Answer)

-1

A ray of light entering from air into a denser medium of refractive index $${4 \over 3}$$, as shown in figure. The light ray suffers total internal reflection at the adjacent surface as shown. The maximum value of angle $$\theta$$ should be equal to :

JEE Main 2021 (Online) 25th July Evening Shift Physics - Geometrical Optics Question 171 English

JEE Main 2021 (Online) 25th July Evening Shift Physics - Geometrical Optics Question 171 English

$${\sin ^{ - 1}}{{\sqrt 7 } \over 3}$$

$${\sin ^{ - 1}}{{\sqrt 5 } \over 4}$$

$${\sin ^{ - 1}}{{\sqrt 7 } \over 4}$$

$${\sin ^{ - 1}}{{\sqrt 5 } \over 3}$$

JEE Main 2021 (Online) 25th July Morning Shift

MCQ (Single Correct Answer)

-1

A ray of laser of a wavelength 630 nm is incident at an angle of 30$$^\circ$$ at the diamond-air interface. It is going from diamond to air. The refractive index of diamond is 2.42 and that of air is 1. Choose the correct option.

angle of refraction is 24.41$$^\circ$$

angle of refraction is 30$$^\circ$$

refraction is not possible

angle of refraction is 53.4$$^\circ$$

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