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JEE Main 2021 (Online) 25th July Evening Shift
+4
-1
A prism of refractive index $$\mu$$ and angle of prism A is placed in the position of minimum angle of deviation. If minimum angle of deviation is also A, then in terms of refractive index
A
$$2{\cos ^{ - 1}}\left( {{\mu \over 2}} \right)$$
B
$${\sin ^{ - 1}}\left( {{\mu \over 2}} \right)$$
C
$${\sin ^{ - 1}}\left( {\sqrt {{{\mu - 1} \over 2}} } \right)$$
D
$${\cos ^{ - 1}}\left( {{\mu \over 2}} \right)$$
2
JEE Main 2021 (Online) 25th July Evening Shift
+4
-1
A ray of light entering from air into a denser medium of refractive index $${4 \over 3}$$, as shown in figure. The light ray suffers total internal reflection at the adjacent surface as shown. The maximum value of angle $$\theta$$ should be equal to : A
$${\sin ^{ - 1}}{{\sqrt 7 } \over 3}$$
B
$${\sin ^{ - 1}}{{\sqrt 5 } \over 4}$$
C
$${\sin ^{ - 1}}{{\sqrt 7 } \over 4}$$
D
$${\sin ^{ - 1}}{{\sqrt 5 } \over 3}$$
3
JEE Main 2021 (Online) 25th July Morning Shift
+4
-1
A ray of laser of a wavelength 630 nm is incident at an angle of 30$$^\circ$$ at the diamond-air interface. It is going from diamond to air. The refractive index of diamond is 2.42 and that of air is 1. Choose the correct option.
A
angle of refraction is 24.41$$^\circ$$
B
angle of refraction is 30$$^\circ$$
C
refraction is not possible
D
angle of refraction is 53.4$$^\circ$$
4
JEE Main 2021 (Online) 25th July Morning Shift
+4
-1
In the Young's double slit experiment, the distance between the slits varies in time as
d(t) = d0 + a0 sin$$\omega$$t; where d0, $$\omega$$ and a0 are constants. The difference between the largest fringe width and the smallest fringe width obtained over time is given as :
A
$${{2\lambda D({d_0})} \over {(d_0^2 - a_0^2)}}$$
B
$${{2\lambda D{a_0}} \over {(d_0^2 - a_0^2)}}$$
C
$${{\lambda D} \over {d_0^2}}{a_0}$$
D
$${{\lambda D} \over {{d_0} + {a_0}}}$$
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