1
JEE Main 2022 (Online) 28th June Morning Shift
+4
-1 The refracting angle of a prism is A and refractive index of the material of the prism is cot (A/2). Then the angle of minimum deviation will be -

A
180 $$-$$ 2A
B
90 $$-$$ A
C
180 + 2A
D
180 $$-$$ 3A
2
JEE Main 2022 (Online) 28th June Morning Shift
+4
-1 The aperture of the objective is 24.4 cm. The resolving power of this telescope, if a light of wavelength 2440 $$\mathop A\limits^o$$ is used to see th object will be :

A
8.1 $$\times$$ 106
B
10.0 $$\times$$ 107
C
8.2 $$\times$$ 105
D
1.0 $$\times$$ 10$$-$$8
3
JEE Main 2022 (Online) 27th June Evening Shift
+4
-1 A convex lens has power P. It is cut into two halves along its principal axis. Further one piece (out of the two halves) is cut into two halves perpendicular to the principal axis (as shown in figures). Choose the incorrect option for the reported pieces. A
Power of $${L_1} = {P \over 2}$$
B
Power of $${L_2} = {P \over 2}$$
C
Power of $${L_3} = {P \over 2}$$
D
Power of L1 = P
4
JEE Main 2022 (Online) 27th June Morning Shift
+4
-1 Consider a light ray travelling in air is incident into a medium of refractive index $$\sqrt{2n}$$. The incident angle is twice that of refracting angle. Then, the angle of incidence will be :

A
$${\sin ^{ - 1}}\left( {\sqrt n } \right)$$
B
$${\cos ^{ - 1}}\left( {\sqrt {{n \over 2}} } \right)$$
C
$${\sin ^{ - 1}}\left( {\sqrt {2n} } \right)$$
D
$$2{\cos ^{ - 1}}\left( {\sqrt {{n \over 2}} } \right)$$
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