JEE Main 2022 (Online) 28th June Morning Shift | Geometrical Optics Question 74 | Physics

The aperture of the objective is 24.4 cm. The resolving power of this telescope, if a light of wavelength 2440 $$\mathop A\limits^o $$ is used to see th object will be :

8.1 $$\times$$ 10⁶

10.0 $$\times$$ 10⁷

8.2 $$\times$$ 10⁵

1.0 $$\times$$ 10^$$-$$8

JEE Main 2022 (Online) 27th June Evening Shift

MCQ (Single Correct Answer)

-1

A convex lens has power P. It is cut into two halves along its principal axis. Further one piece (out of the two halves) is cut into two halves perpendicular to the principal axis (as shown in figures). Choose the incorrect option for the reported pieces.

JEE Main 2022 (Online) 27th June Evening Shift Physics - Geometrical Optics Question 79 English

Power of $${L_1} = {P \over 2}$$

Power of $${L_2} = {P \over 2}$$

Power of $${L_3} = {P \over 2}$$

Power of L₁ = P

JEE Main 2022 (Online) 27th June Morning Shift

MCQ (Single Correct Answer)

-1

Consider a light ray travelling in air is incident into a medium of refractive index $$\sqrt{2n}$$. The incident angle is twice that of refracting angle. Then, the angle of incidence will be :

$${\sin ^{ - 1}}\left( {\sqrt n } \right)$$

$${\cos ^{ - 1}}\left( {\sqrt {{n \over 2}} } \right)$$

$${\sin ^{ - 1}}\left( {\sqrt {2n} } \right)$$

$$2{\cos ^{ - 1}}\left( {\sqrt {{n \over 2}} } \right)$$

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