JEE Main 2019 (Online) 10th January Evening Slot | Ray & Wave Optics Question 190 | Physics

JEE Main 2019 (Online) 10th January Evening Slot

MCQ (Single Correct Answer)

-1

The eye can be regarded as a single refracting surface. The radius of curvature of this surface is equal to that of cornea (7.8 mm). This surface separateds two media of refractive indices 1 and 1.34. Calculate the distance from the refracting surface at which a parallel beam of light will come to focus -

2 cm

3.1 cm

4.0 cm

1 cm

JEE Main 2019 (Online) 10th January Evening Slot

MCQ (Single Correct Answer)

-1

Consider a Young’s double slit experiment as shown in figure. What should be the slit separation d in terms of wavelength $$\lambda $$ such that the first minima occurs directly in front of the slit (S₁) ?

JEE Main 2019 (Online) 10th January Evening Slot Physics - Ray & Wave Optics Question 190 English

JEE Main 2019 (Online) 10th January Evening Slot Physics - Ray & Wave Optics Question 190 English

$${\lambda \over {2\left( {5 - \sqrt 2 } \right)}}$$

$${\lambda \over {2\left( {\sqrt 5 - 2} \right)}}$$

$${\lambda \over {\left( {5 - \sqrt 2 } \right)}}$$

$${\lambda \over {\left( {\sqrt 5 - 2} \right)}}$$

JEE Main 2019 (Online) 10th January Morning Slot

MCQ (Single Correct Answer)

-1

In a Young’s double slit experiment with slit separation 0.1 mm, one observes a bright fringe at angle $${1 \over {40}}$$ by using light of wavelength $$\lambda $$₁. When the light of wavelength $$\lambda $$₂ is used a bright fringe is seen at the same angle in the same set up. Given that $$\lambda $$₁ and $$\lambda $$₂ are in visible range (380 nm to 740 nm), their values are -

400 nm, 500 nm

625 nm, 500 nm

380 nm, 500 nm

380 nm, 525 nm

JEE Main 2019 (Online) 10th January Morning Slot

MCQ (Single Correct Answer)

-1

A plano convex lens of refractive index $$\mu $$₁ and focal length ƒ₁ is kept in contact with another plano concave lens of refractive index $$\mu $$₂ and focal length ƒ₂. If the radius of curvature of their spherical faces is R each and ƒ₁ = 2ƒ₂, then $$\mu $$₁ and $$\mu $$₂ are related as -

$$3{\mu _2} - 2{\mu _1}$$ = 1

$${\mu _1} + {\mu _2}$$ = 3

$$2{\mu _1} - {\mu _2}$$ = 1

$$2{\mu _2} - {\mu _1}$$ = 1

PREVIOUS NEXT