JEE Main 2019 (Online) 12th April Evening Slot | Ray & Wave Optics Question 160 | Physics

JEE Main 2019 (Online) 12th April Evening Slot

MCQ (Single Correct Answer)

-1

A transparent cube of side, made of a material of refractive index $$\mu $$₂, is immersed in a liquid of refractive index $$\mu $$₁($$\mu $$₁ < $$\mu $$₂). A ray is incident on the face AB at an angle $$\theta $$(shown in the figure). Total internal reflection takes place at point E on the face BC. JEE Main 2019 (Online) 12th April Evening Slot Physics - Ray & Wave Optics Question 161 English

JEE Main 2019 (Online) 12th April Evening Slot Physics - Ray & Wave Optics Question 161 English

Then $$\theta $$ must satisfy :

$$\theta > {\sin ^{ - 1}}\sqrt {{{\mu _2^2} \over {\mu _1^2}} - 1} $$

$$\theta < {\sin ^{ - 1}}\sqrt {{{\mu _2^2} \over {\mu _1^2}} - 1} $$

$$\theta < {\sin ^{ - 1}}{{{\mu _1}} \over {{\mu _2}}}$$

$$\theta > {\sin ^{ - 1}}{{{\mu _1}} \over {{\mu _2}}}$$

JEE Main 2019 (Online) 12th April Evening Slot

MCQ (Single Correct Answer)

-1

A system of three polarizers P₁, P₂, P₃ is set up such that the pass axis of P₃ is crossed with respect to that of P₁. The pass axis of P₂ is inclined at 60^o to the pass axis of P₃. When a beam of unpolarized light of intensity I0 is incident on P₁, the intensity of light transmitted by the three polarizers is I. The ratio ($${{{I_0}} \over I}$$) equals (nearly) :

10.67

5.33

16.00

1.80

JEE Main 2019 (Online) 12th April Morning Slot

MCQ (Single Correct Answer)

-1

The value of numerical aperature of the objective lens of a microscope is 1.25. If light of wavelength 5000 $$\mathop A\limits^o $$ is used, the minimum separation between two points, to be seen as distinct, will be :

0.12 $$\mu $$m

0.38 $$\mu $$m

0.24 $$\mu $$m

0.48 $$\mu $$m

JEE Main 2019 (Online) 12th April Morning Slot

MCQ (Single Correct Answer)

-1

In a double slit experiment, when a thin film of thickness t having refractive index $$\mu $$. is introduced in front of one of the slits, the maximum at the centre of the fringe pattern shifts by one fringe width. The value of t is ($$\lambda $$ is the wavelength of the light used) :

$${\lambda \over {2\left( {\mu - 1} \right)}}$$

$${\lambda \over {\left( {2\mu - 1} \right)}}$$

$${{2\lambda } \over {\left( {\mu - 1} \right)}}$$

$${\lambda \over {\left( {\mu - 1} \right)}}$$

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