AIEEE 2005 | Atoms and Nuclei Question 238 | Physics

The binding energy per nucleon of deuteron $$\left( {{}_1^2\,H} \right)$$ and helium nucleus $$\left( {{}_2^4\,He} \right)$$ is $$1.1$$ $$MeV$$ and $$7$$ $$MeV$$ respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

$$23.6\,\,MeV$$

$$26.9\,\,MeV$$

$$13.9\,\,MeV$$

$$19.2\,\,MeV$$

AIEEE 2004

MCQ (Single Correct Answer)

-1

Out of Syllabus

A nucleus disintegrated into two nuclear parts which have their velocities in the ratio of $$2:1.$$ The ratio of their nuclear sizes will be

$${3^{{\raise0.5ex\hbox{$\scriptstyle 1$} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{$\scriptstyle 2$}}}}:1$$

$$1:{2^{1/3}}$$

$${2^{1/3}}:1$$

$$1:{3^{{\raise0.5ex\hbox{$\scriptstyle 1$} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{$\scriptstyle 2$}}}}$$

AIEEE 2004

MCQ (Single Correct Answer)

-1

An $$\alpha $$-particle of energy $$5$$ $$MeV$$ is scattered through $${180^ \circ }$$ by a fixed uranium nucleus. The distance of closest approach is of the order of

$${10^{ - 12}}\,cm$$

$${10^{ - 10}}\,cm$$

$$1A$$

$${10^{ - 15a}}\,cm$$

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