An electron of a hydrogen like atom, having $$Z=4$$, jumps from $$4^{\text {th }}$$ energy state to $$2^{\text {nd }}$$ energy state. The energy released in this process, will be :
(Given Rch = $$13.6~\mathrm{eV}$$)
Where R = Rydberg constant
c = Speed of light in vacuum
h = Planck's constant
A proton moving with one tenth of velocity of light has a certain de Broglie wavelength of $$\lambda$$. An alpha particle having certain kinetic energy has the same de-Brogle wavelength $$\lambda$$. The ratio of kinetic energy of proton and that of alpha particle is:
Match List I with List II :
List I | List II | ||
---|---|---|---|
A. | Microwaves | I. | Radio active decay of the nucleus |
B. | Gamma rays | II. | Rapid acceleration and deceleration of electron in aerials |
C. | Radio waves | III. | Inner shell electrons |
D. | X-rays | IV. | Klystron valve |
Choose the correct answer from the options given below :
The mass of proton, neutron and helium nucleus are respectively $$1.0073~u,1.0087~u$$ and $$4.0015~u$$. The binding energy of helium nucleus is :