JEE Main 2019 (Online) 9th April Evening Slot | Atoms and Nuclei Question 181 | Physics

Taking the wavelength of first Balmer line in hydrogen spectrum (n = 3 to n = 2) as 660 nm, the wavelength of the 2nd Balmer line (n = 4 to n = 2) will be :

642.7 nm

488.9 nm

889.2 nm

388.9 nm

JEE Main 2019 (Online) 8th April Evening Slot

MCQ (Single Correct Answer)

-1

The ratio of mass densities of nuclei of ⁴⁰Ca and ¹⁶O is close to :-

0.1

JEE Main 2019 (Online) 8th April Morning Slot

MCQ (Single Correct Answer)

-1

Radiation coming from transitions n = 2 to n = 1 of hydrogen atoms fall on He⁺ ions in n = 1 and n = 2 states. The possible transition of helium ions as they absorb energy from the radiation is :

n = 1 $$ \to $$ n = 4

n = 2 $$ \to $$ n = 5

n = 2 $$ \to $$ n = 4

n = 2 $$ \to $$ n = 3

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