JEE Main 2024 (Online) 5th April Evening Shift | Atoms and Nuclei Question 13 | Physics

An electron rotates in a circle around a nucleus having positive charge $$\mathrm{Ze}$$. Correct relation between total energy (E) of electron to its potential energy (U) is :

$$2 \mathrm{E}=3 \mathrm{U}$$

$$\mathrm{E}=\mathrm{U}$$

$$2 \mathrm{E}=\mathrm{U}$$

$$\mathrm{E}=2 \mathrm{U}$$

JEE Main 2024 (Online) 4th April Evening Shift

MCQ (Single Correct Answer)

-1

According to Bohr's theory, the moment of momentum of an electron revolving in $$4^{\text {th }}$$ orbit of hydrogen atom is:

$$2 \frac{h}{\pi}$$

$$\frac{h}{2 \pi}$$

$$\frac{h}{\pi}$$

$$8 \frac{h}{\pi}$$

JEE Main 2024 (Online) 4th April Morning Shift

MCQ (Single Correct Answer)

-1

Which of the following nuclear fragments corresponding to nuclear fission between neutron $$\left({ }_0^1 \mathrm{n}\right)$$ and uranium isotope $$\left({ }_{92}^{235} \mathrm{U}\right)$$ is correct :

$${ }_{56}^{140} \mathrm{Xe}+{ }_{38}^{94} \mathrm{Sr}+3{ }_0^1 \mathrm{n}$$

$${ }_{51}^{153} \mathrm{Sb}+{ }_{41}^{99} \mathrm{Nb}+3{ }_0^1 \mathrm{n}$$

$${ }_{56}^{144} \mathrm{Ba}+{ }_{36}^{89} \mathrm{Kr}+4{ }_0^1 \mathrm{n}$$

$${ }_{56}^{144} \mathrm{Ba}+{ }_{36}^{89} \mathrm{Kr}+3{ }_0^1 \mathrm{n}$$

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