1
JEE Main 2026 (Online) 24th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements :

Statement I : For all elements, greater the mass of the nucleus, greater is the binding energy per nucleon.

Statement II : For all elements, nuclei with less binding energy per nucleon transforms to nuclei with greater binding energy per nucleon.

In the light of the above statements, choose the correct answer from the options given below

A

Statement I is false but Statement II is true

B

Both Statement I and Statement II are true

C

Both Statement I and Statement II are false

D

Statement I is true but Statement II is false

2
JEE Main 2026 (Online) 23rd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Which of the following pair of nuclei are isobars of the element?

A

${ }_1^3 \mathrm{H}$ and ${ }_2^3 \mathrm{He}$

B

${ }_{80}^{198} \mathrm{Hg}$ and ${ }_{79}^{197} \mathrm{Au}$

C

${ }_1^2 \mathrm{H}$ and ${ }_1^3 \mathrm{H}$

D

${ }_{92}^{236} \mathrm{U}$ and ${ }_{92}^{238} \mathrm{U}$

3
JEE Main 2026 (Online) 23rd January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

In hydrogen atom spectrum, ( $R \rightarrow$ Rydberg's constant)

A. the maximum wavelength of the radiation of Lyman series is $\frac{4}{3 R}$

B. the Balmer series lies in the visible region of the spectrum

C. the minimum wavelength of the radiation of Paschen series is $\frac{9}{R}$

D. the minimum wavelength of Lyman series is $\frac{5}{4 R}$

Choose the correct answer from the options given below :

A

A, B Only

B

B, D Only

C

A, B and D Only

D

A, B and C Only

4
JEE Main 2026 (Online) 22nd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The smallest wavelength of Lyman series is 91 nm . The difference between the largest wavelengths of Paschen and Balmer series is nearly $\_\_\_\_$ nm.

A

1784

B

1875

C

1217

D

1550

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