JEE Main 2019 (Online) 11th January Evening Slot | s-Block Elements Question 98 | Chemistry

Item I		Item II
(i)	Na₂CO₃.10H₂O	(A)	Portland cement ingredient
(ii)	Mg(HCO₃)₂	(B)	Castner-Kellner process
(iii)	NaOH	(C)	Solvay process
(iv)	Ca₃Al₂O₆	(D)	Temporary hardness

(i)$$ \to $$(D); (ii)$$ \to $$(A); (iii)$$ \to $$(B); (iv)$$ \to $$(C)

(i)$$ \to $$(B); (ii)$$ \to $$(C); (iii)$$ \to $$(A); (iv)$$ \to $$(D)

(i)$$ \to $$(C); (ii)$$ \to $$(B); (iii)$$ \to $$(D); (iv)$$ \to $$(A)

(i)$$ \to $$(C); (ii)$$ \to $$(D); (iii)$$ \to $$(B); (iv)$$ \to $$(A)

JEE Main 2019 (Online) 11th January Evening Slot

MCQ (Single Correct Answer)

-1

Out of Syllabus

The reaction that does NOT define calcination is :

2Cu₂S + 3O₂ $$\buildrel \Delta \over \longrightarrow $$ 2Cu₂O + 2SO₂

CaCO₃ . MgCO₃ $$\buildrel \Delta \over \longrightarrow $$ CaO + MgO + 2CO₂

ZnCO₃ $$\buildrel \Delta \over \longrightarrow $$ ZnO + CO₂

Fe₂O₃ . XH₂O $$\buildrel \Delta \over \longrightarrow $$ Fe₂O₃ + XH₂O

JEE Main 2019 (Online) 11th January Morning Slot

MCQ (Single Correct Answer)

-1

Out of Syllabus

The amphoteric hydroxide is :

Ca(OH)₂

Be(OH)₂

Mg(OH)₂

Sr(OH)₂

JEE Main 2019 (Online) 10th January Evening Slot

MCQ (Single Correct Answer)

-1

Out of Syllabus

Sodium metal on dissolution in liquid ammonia gives a deep blue solution due to the formation of :

ammoniated electrons

sodamide

sodium-ammonia complex

sodium ion-ammonia complex

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