JEE Main 2019 (Online) 10th April Evening Slot | Magnetics Question 178 | Physics

JEE Main 2019 (Online) 10th April Evening Slot

MCQ (Single Correct Answer)

-1

A square loop is carrying a steady current I and the magnitude of its magnetic dipole moment is m. if this square loop is changed to a circular loop and it carries the same current, the magnitude of the magnetic dipole moment of circular loop will be:

$${m \over \pi }$$

$${{3m} \over \pi }$$

$${{2m} \over \pi }$$

$${{4m} \over \pi }$$

JEE Main 2019 (Online) 10th April Evening Slot

MCQ (Single Correct Answer)

-1

The magnitude of the magnetic field at the centre of an equilateral triangular loop of side 1 m which is carrying a current of 10 A is :
[Take $$\mu $$₀ = 4$$\pi $$ × 10^–7 NA^–2]

3 $$\mu $$T

18 $$\mu $$T

9 $$\mu $$T

1 $$\mu $$T

JEE Main 2019 (Online) 10th April Morning Slot

MCQ (Single Correct Answer)

-1

A proton, an electron, and a Helium nucleus, have the same energy. They are in circular orbits in a plane due to magnetic field perpendicualr to the plane. Let r_p, r_e and r_He be their respective radii, then

r_e < r_p < r_He

r_e< r_p= r_He

r_e > r_p > r_He

r_e > r_p = r_He

JEE Main 2019 (Online) 9th April Evening Slot

MCQ (Single Correct Answer)

-1

Two coils 'P' and 'Q' are separated by some distance. When a current of 3 A flows through coil 'P', a magnetic flux of 10^–3 Wb passes through 'Q'. No current is passed through 'Q'. When no current passes through 'P' and a current of 2 A passes through 'Q', the flux through 'P' is :-

3.67 × 10^–4 Wb

3.67 × 10^–3 Wb

6.67 × 10^–4 Wb

6.67 × 10^–3 Wb

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