AIEEE 2007 | Magnetic Effect of Current Question 181 | Physics

Two identical conducting wires $$AOB$$ and $$COD$$ are placed at right angles to each other. The wire $$AOB$$ carries an electric current $${I_1}$$ and $$COD$$ carries a current $${I_2}$$. The magnetic field on a point lying at a distance $$d$$ from $$O$$, in a direction perpendicular to the plane of the wires $$AOB$$ and $$COD$$ , will be given by

$${{{\mu _0}} \over {2\pi d}}\left( {I_1^2 + I_2^2} \right)$$

$${{{\mu _0}} \over {2\pi }}{\left( {{{{I_1} + {I_2}} \over d}} \right)^{{1 \over 2}}}$$

$${{{\mu _0}} \over {2\pi d}}{\left( {I_1^2 + I_2^2} \right)^{{1 \over 2}}}$$

$${{{\mu _0}} \over {2\pi d}}\left( {{I_1} + {I_2}} \right)$$

AIEEE 2006

MCQ (Single Correct Answer)

-1

In a region, steady and uniform electric and magnetic fields are present. These two fields are parallel to each other. A charged particle is released from rest in this region. The path of the particle will be a

helix

straight line

ellipse

circle

AIEEE 2006

MCQ (Single Correct Answer)

-1

A long solenoid has $$200$$ turns per $$cm$$ and carries a current $$i.$$ The magnetic field at its center is $$6.28 \times {10^{ - 2}}\,\,\,Weber/{m^2}.$$ Another long solenoid has $$100$$ turns per $$cm$$ and it carries a current $${i \over 3}$$. The value of the magnetic field at its center is

$$1.05 \times {10^{ - 2}}\,\,Weber/{m^2}$$

$$1.05 \times {10^{ - 5}}\,\,Weber/{m^2}$$

$$1.05 \times {10^{ - 3}}\,\,Weber/{m^2}$$

$$1.05 \times {10^{ - 4}}\,\,Weber/{m^2}$$

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