JEE Main 2025 (Online) 2nd April Evening Shift | Geometrical Optics Question 52 | Physics

A bi-convex lens has radius of curvature of both the surfaces same as $1 / 6 \mathrm{~cm}$. If this lens is required to be replaced by another convex lens having different radii of curvatures on both sides $\left(R_1 \neq R_2\right)$, without any change in lens power then possible combination of $R_1$ and $R_2$ is :

$\frac{1}{3} \mathrm{~cm}$ and $\frac{1}{7} \mathrm{~cm}$

$\frac{1}{5} \mathrm{~cm}$ and $\frac{1}{7} \mathrm{~cm}$

$\frac{1}{3} \mathrm{~cm}$ and $\frac{1}{3} \mathrm{~cm}$

$\frac{1}{6} \mathrm{~cm}$ and $\frac{1}{9} \mathrm{~cm}$

JEE Main 2025 (Online) 2nd April Morning Shift

MCQ (Single Correct Answer)

-1

JEE Main 2025 (Online) 2nd April Morning Shift Physics - Geometrical Optics Question 51 English

A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the image of an object ' O ', is :

( C is the center of curvature of the spherical surface and R is the radius of curvature)

0.24 m left to the spherical surface

0.24 m right to the spherical surface

0.4 m left to the spherical surface

0.4 m right to the spherical surface

JEE Main 2025 (Online) 2nd April Morning Shift

MCQ (Single Correct Answer)

-1

A slanted object $A B$ is placed on one side of convex lens as shown in the diagram. The image is formed on the opposite side. Angle made by the image with principal axis is :

JEE Main 2025 (Online) 2nd April Morning Shift Physics - Geometrical Optics Question 52 English

$-\alpha$

$-\frac{\alpha}{2}$

$-45^{\circ}$

$+45^{\circ}$

JEE Main 2025 (Online) 29th January Evening Shift

MCQ (Single Correct Answer)

-1

A convex lens made of glass (refractive index = 1.5) has focal length 24 cm in air. When it is totally immersed in water (refractive index = 1.33), its focal length changes to

96 cm

72 cm

24 cm

48 cm

PREVIOUS NEXT

Questions from Geometrical Optics

MCQ (Single Correct Answer) · No. in brackets = question count