AIEEE 2004 | Motion Question 180 | Physics

A ball is thrown from a point with a speed ν₀ at an angle of projection θ. From the same point and at the same instant person starts running with a constant speed $${{{v_0}} \over 2}$$ to catch the ball. Will the person be able to catch the ball? If yes, what should be the angle of projection θ?

Yes, $$30^\circ $$

Yes, $$60^\circ $$

Yes, $$45^\circ $$

AIEEE 2003

MCQ (Single Correct Answer)

-1

A car, moving with a speed of 50 km/hr, can be stopped by brakes after at least 6 m. If the same car is moving at a speed of 100 km/hr, the minimum stopping distance is

12 m

18 m

24 m

6 m

AIEEE 2003

MCQ (Single Correct Answer)

-1

A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle of $$30^\circ $$ with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground? $$\left[ {g = 10m/{s^2},\sin 30^\circ = {1 \over 2},\cos 30^\circ = {{\sqrt 3 } \over 2}} \right]$$

5.20 m

4.33 m

2.60 m

8.66 m

AIEEE 2003

MCQ (Single Correct Answer)

-1

The co-ordinates of a moving particle at any time 't' are given by x = $$\alpha $$t³ and y = βt³. The speed to the particle at time 't' is given by

$$3t\sqrt {{\alpha ^2} + {\beta ^2}} $$

$$3{t^2}\sqrt {{\alpha ^2} + {\beta ^2}} $$

$${t^2}\sqrt {{\alpha ^2} + {\beta ^2}} $$

$$\sqrt {{\alpha ^2} + {\beta ^2}} $$