JEE Main 2021 (Online) 26th February Morning Shift | Properties of Matter Question 165 | Physics

The normal density of a material is $$\rho$$ and its bulk modulus of elasticity is K. The magnitude of increase in density of material, when a pressure P is applied uniformly on all sides, will be :

$${{\rho K} \over P}$$

$${{PK} \over \rho }$$

$${{\rho P} \over K}$$

$${K \over {\rho P}}$$

JEE Main 2021 (Online) 24th February Morning Shift

MCQ (Single Correct Answer)

-1

If Y, K and $$\eta $$ are the values of Young's modulus, bulk modulus and modulus of rigidity of any material respectively. Choose the correct relation for these parameters.

$$Y = {{9K\eta } \over {3K - \eta }}N/{m^2}$$

$$Y = {{9K\eta } \over {2\eta + 3K}}N/{m^2}$$

$$\eta = {{3YK} \over {9K + Y}}N/{m^2}$$

$$K = {{Y\eta } \over {9\eta - 3Y}}N/{m^2}$$

JEE Main 2020 (Online) 6th September Evening Slot

MCQ (Single Correct Answer)

-1

A fluid is flowing through a horizontal pipe of varying cross-section, with
speed v ms^–1 at a point where the pressure is P pascal. At another point where pressure is $${P \over 2}$$ Pascal its speed is V ms^–1. If the density of the fluid is $$\rho $$ kg m^–3 and the flow is streamline, then V is equal to :

$$\sqrt {{P \over {2\rho }} + {v^2}} $$

$$\sqrt {{P \over \rho } + {v^2}} $$

$$\sqrt {{{2P} \over \rho } + {v^2}} $$

$$\sqrt {{P \over \rho } + {v}} $$

JEE Main 2020 (Online) 6th September Morning Slot

MCQ (Single Correct Answer)

-1

An object of mass m is suspended at the end of a massless wire of length L and area of crosssection A. Young modulus of the material of the wire is Y. If the mass is pulled down slightly its frequency of oscillation along the vertical direction is :

$$f = {1 \over {2\pi }}\sqrt {{{YA} \over {mL}}} $$

$$f = {1 \over {2\pi }}\sqrt {{{mL} \over {YA}}} $$

$$f = {1 \over {2\pi }}\sqrt {{{YL} \over {mA}}} $$

$$f = {1 \over {2\pi }}\sqrt {{{mA} \over {YL}}} $$

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