1
JEE Main 2024 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A cube of ice floats partly in water and partly in kerosene oil. The ratio of volume of ice immersed in water to that in kerosene oil (specific gravity of Kerosene oil = 0.8, specific gravity of ice = 0.9):

JEE Main 2024 (Online) 8th April Evening Shift Physics - Properties of Matter Question 44 English

A
5 : 4
B
9 : 10
C
8 : 9
D
1 : 1
2
JEE Main 2024 (Online) 8th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Young's modulus is determined by the equation given by $$\mathrm{Y}=49000 \frac{\mathrm{m}}{\mathrm{l}} \frac{\mathrm{dyne}}{\mathrm{cm}^2}$$ where $$M$$ is the mass and $$l$$ is the extension of wire used in the experiment. Now error in Young modules $$(Y)$$ is estimated by taking data from $$M-l$$ plot in graph paper. The smallest scale divisions are $$5 \mathrm{~g}$$ and $$0.02 \mathrm{~cm}$$ along load axis and extension axis respectively. If the value of $M$ and $l$ are $$500 \mathrm{~g}$$ and $$2 \mathrm{~cm}$$ respectively then percentage error of $$Y$$ is :

A
2%
B
0.02%
C
0.5%
D
0.2%
3
JEE Main 2024 (Online) 8th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Correct Bernoulli's equation is (symbols have their usual meaning) :

A
$$P+\frac{1}{2} \rho g h+\frac{1}{2} \rho v^2=$$ constant
B
$$P+m g h+\frac{1}{2} m v^2=$$ constant
C
$$P+\rho g h+\rho v^2=$$ constant
D
$$P+\rho g h+\frac{1}{2} \rho v^2=$$ constant
4
JEE Main 2024 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Pressure inside a soap bubble is greater than the pressure outside by an amount : (given : $$\mathrm{R}=$$ Radius of bubble, $$\mathrm{S}=$$ Surface tension of bubble)

A
$$\frac{S}{R}$$
B
$$\frac{4 \mathrm{~S}}{\mathrm{R}}$$
C
$$\frac{4 \mathrm{R}}{\mathrm{S}}$$
D
$$\frac{2 S}{R}$$
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