JEE Main 2022 (Online) 24th June Evening Shift | Properties of Matter Question 133 | Physics

Potential energy as a function of r is given by $$U = {A \over {{r^{10}}}} - {B \over {{r^5}}}$$, where r is the interatomic distance, A and B are positive constants. The equilibrium distance between the two atoms will be :

$${\left( {{A \over B}} \right)^{{1 \over 5}}}$$

$${\left( {{B \over A}} \right)^{{1 \over 5}}}$$

$${\left( {{2A \over B}} \right)^{{1 \over 5}}}$$

$${\left( {{B \over 2A}} \right)^{{1 \over 5}}}$$

JEE Main 2022 (Online) 24th June Morning Shift

MCQ (Single Correct Answer)

-1

The bulk modulus of a liquid is 3 $$\times$$ 10¹⁰ Nm^$$-$$2. The pressure required to reduce the volume of liquid by 2% is :

3 $$\times$$ 10⁸ Nm^$$-$$2

9 $$\times$$ 10⁸ Nm^$$-$$2

6 $$\times$$ 10⁸ Nm^$$-$$2

12 $$\times$$ 10⁸ Nm^$$-$$2

JEE Main 2021 (Online) 31st August Evening Shift

MCQ (Single Correct Answer)

-1

Four identical hollow cylindrical columns of mild steel support a big structure of mass 50 $$\times$$ 10³ kg. The inner and outer radii of each column are 50 cm and 100 cm respectively. Assuming uniform local distribution, calculate the compression strain of each column. [Use Y = 2.0 $$\times$$ 10¹¹ Pa, g = 9.8 m/s²]

3.60 $$\times$$ 10^$$-$$8

2.60 $$\times$$ 10^$$-$$7

1.87 $$\times$$ 10^$$-$$3

7.07 $$\times$$ 10^$$-$$4

JEE Main 2021 (Online) 31st August Morning Shift

MCQ (Single Correct Answer)

-1

A uniform heavy rod of weight 10 kg ms^$$-$$2, cross-sectional area 100 cm² and length 20 cm is hanging from a fixed support. Young modulus of the material of the rod is 2 $$\times$$ 10¹¹ Nm^$$-$$2. Neglecting the lateral contraction, find the elongation of rod due to its own weight.

2 $$\times$$ 10^$$-$$9 m

5 $$\times$$ 10^$$-$$8 m

4 $$\times$$ 10^$$-$$8 m

5 $$\times$$ 10^$$-$$10 m

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