1
JEE Main 2024 (Online) 30th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

All surfaces shown in figure are assumed to be frictionless and the pulleys and the string are light. The acceleration of the block of mass $$2 \mathrm{~kg}$$ is :

JEE Main 2024 (Online) 30th January Morning Shift Physics - Laws of Motion Question 16 English

A
$$\mathrm{\frac{g}{2}}$$
B
$$\mathrm{\frac{g}{4}}$$
C
$$\mathrm{g}$$
D
$$\mathrm{\frac{g}{3}}$$
2
JEE Main 2024 (Online) 27th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements :

Statement (I) : The limiting force of static friction depends on the area of contact and independent of materials.

Statement (II) : The limiting force of kinetic friction is independent of the area of contact and depends on materials.

In the light of the above statements, choose the most appropriate answer from the options given below :

A
Statement I is incorrect but Statement II is correct
B
Both Statement I and Statement II are correct
C
Both Statement I and Statement II are incorrect
D
Statement I is correct but Statement II is incorrect
3
JEE Main 2023 (Online) 15th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
The position vector of a particle related to time $t$ is given by

$\vec{r}=\left(10 t \hat{i}+15 t^{2} \hat{j}+7 \hat{k}\right) m$

The direction of net force experienced by the particle is :
A
Positive $x$ - axis
B
Positive $y$ - axis
C
Positive $z$ - axis
D
In $x$ - $y$ plane
4
JEE Main 2023 (Online) 12th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Three forces $$F_{1}=10 \mathrm{~N}, F_{2}=8 \mathrm{~N}, \mathrm{~F}_{3}=6 \mathrm{~N}$$ are acting on a particle of mass $$5 \mathrm{~kg}$$. The forces $$\mathrm{F}_{2}$$ and $$\mathrm{F}_{3}$$ are applied perpendicularly so that particle remains at rest. If the force $$F_{1}$$ is removed, then the acceleration of the particle is:

A
$$4.8 \mathrm{~ms}^{-2}$$
B
$$7 \mathrm{~ms}^{-2}$$
C
$$2 \mathrm{~ms}^{-2}$$
D
$$0.5 \mathrm{~ms}^{-2}$$
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