1
JEE Main 2023 (Online) 11th April Evening Shift
+4
-1

A body of mass $$500 \mathrm{~g}$$ moves along $$\mathrm{x}$$-axis such that it's velocity varies with displacement $$\mathrm{x}$$ according to the relation $$v=10 \sqrt{x} \mathrm{~m} / \mathrm{s}$$ the force acting on the body is:-

A
166 N
B
5 N
C
25 N
D
125 N
2
JEE Main 2023 (Online) 8th April Morning Shift
+4
-1

At any instant the velocity of a particle of mass $$500 \mathrm{~g}$$ is $$\left(2 t \hat{i}+3 t^{2} \hat{j}\right) \mathrm{ms}^{-1}$$. If the force acting on the particle at $$t=1 \mathrm{~s}$$ is $$(\hat{i}+x \hat{j}) \mathrm{N}$$. Then the value of $$x$$ will be:

A
2
B
4
C
6
D
3
3
JEE Main 2023 (Online) 1st February Evening Shift
+4
-1

As shown in the figure a block of mass 10 kg lying on a horizontal surface is pulled by a force F acting at an angle $$30^\circ$$, with horizontal. For $$\mu_s=0.25$$, the block will just start to move for the value of F : [Given $$g=10~\mathrm{ms}^{-2}$$]

A
25.2 N
B
35.7 N
C
20 N
D
33.3 N
4
JEE Main 2023 (Online) 1st February Evening Shift
+4
-1

Figures (a), (b), (c) and (d) show variation of force with time.

The impulse is highest in figure.

A
Fig (c)
B
Fig (d)
C
Fig (a)
D
Fig (b)
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