JEE Main 2023 (Online) 31st January Evening Shift | Laws of Motion Question 33 | Physics

A body of mass $10 \mathrm{~kg}$ is moving with an initial speed of $20 \mathrm{~m} / \mathrm{s}$. The body stops after $5 \mathrm{~s}$ due to friction between body and the floor. The value of the coefficient of friction is:

(Take acceleration due to gravity $g=10 \mathrm{~ms}^{-2}$ )

0.3

0.2

0.5

0.4

JEE Main 2023 (Online) 31st January Morning Shift

MCQ (Single Correct Answer)

-1

As shown in figure, a $$70 \mathrm{~kg}$$ garden roller is pushed with a force of $$\vec{F}=200 \mathrm{~N}$$ at an angle of $$30^{\circ}$$ with horizontal. The normal reaction on the roller is

(Given $$\mathrm{g=10~m~s^{-2}}$$)

JEE Main 2023 (Online) 31st January Morning Shift Physics - Laws of Motion Question 38 English

800 N

600 N

200$$\sqrt3$$ N

800$$\sqrt2$$ N

JEE Main 2023 (Online) 30th January Evening Shift

MCQ (Single Correct Answer)

-1

A block of $\sqrt{3} \mathrm{~kg}$ is attached to a string whose other end is attached to the wall. An unknown force $\mathrm{F}$ is applied so that the string makes an angle of $30^{\circ}$ with the wall. The tension $\mathrm{T}$ is: (Given $\mathrm{g}=10 \mathrm{~ms}^{-2}$ )

JEE Main 2023 (Online) 30th January Evening Shift Physics - Laws of Motion Question 37 English

JEE Main 2023 (Online) 30th January Evening Shift Physics - Laws of Motion Question 37 English

15 N

10 N

25 N

20 N

JEE Main 2023 (Online) 29th January Evening Shift

MCQ (Single Correct Answer)

-1

A force acts for 20 s on a body of mass 20 kg, starting from rest, after which the force ceases and then body describes 50 m in the next 10 s. The value of force will be:

40 N

20 N

5 N

10 N

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