JEE Main 2019 (Online) 9th January Evening Slot | Gravitation Question 111 | Physics

JEE Main 2019 (Online) 9th January Evening Slot

MCQ (Single Correct Answer)

-1

The energy required to take a satellite to a height 'h' above Earth surface (radius of Earth = 6.4 $$ \times $$ 10³ km) is E₁ and kinetic energy required for the satellite to be in a circular orbit at this height is E₂. The value of h for which E₁ and E₂ are equal, is

1.6 $$ \times $$ 10³ km

3.2 $$ \times $$ 10³ km

6.4 $$ \times $$ 10³ km

1.28 $$ \times $$ 10⁴ km

JEE Main 2018 (Online) 16th April Morning Slot

MCQ (Single Correct Answer)

-1

Suppose that the angular velocity of rotation of earth is increased. Then, as a consequence :

Weight of the object, everywhere on the earth, will increase.

Weight of the object, everywhere on the earth, will decrease.

There will be no change in weight anywhere on the earth.

Except at poles, weight of the object on the earth will decrease.

JEE Main 2018 (Offline)

MCQ (Single Correct Answer)

-1

A particle is moving in a circular path of radius $$a$$ under the action of an attractive potential $$U = - {k \over {2{r^2}}}$$ Its total energy is:

$$ - {3 \over 2}{k \over {{a^2}}}$$

Zero

$$ - {k \over {4{a^2}}}$$

$$ {k \over {2{a^2}}}$$

JEE Main 2018 (Offline)

MCQ (Single Correct Answer)

-1

A particle is moving with a uniform speed in a circular orbit of radius R in a central force inversely proportional to the n^th power of R. If the period of rotation of the particle is T, then :

T $$ \propto $$ R^n/2

T $$ \propto $$ R^3/2 for any n

T $$ \propto $$ R^{n/2 +1}

T $$ \propto $$ R^(n+1)/2

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