JEE Main 2022 (Online) 24th June Evening Shift | Gravitation Question 88 | Physics

Four particles each of mass M, move along a circle of radius R under the action of their mutual gravitational attraction as shown in figure. The speed of each particle is :

JEE Main 2021 (Online) 1st September Evening Shift Physics - Gravitation Question 92 English

JEE Main 2021 (Online) 1st September Evening Shift Physics - Gravitation Question 92 English

$${1 \over 2}\sqrt {{{GM} \over {R(2\sqrt 2 + 1)}}} $$

$${1 \over 2}\sqrt {{{GM} \over R}(2\sqrt 2 + 1)} $$

$${1 \over 2}\sqrt {{{GM} \over R}(2\sqrt 2 - 1)} $$

$$\sqrt {{{GM} \over R}} $$

JEE Main 2021 (Online) 31st August Evening Shift

MCQ (Single Correct Answer)

-1

If R_E be the radius of Earth, then the ratio between the acceleration due to gravity at a depth 'r' below and a height 'r' above the earth surface is : (Given : r < R_E)

$$1 - {r \over {{R_E}}} - {{{r^2}} \over {R_E^2}} - {{{r^3}} \over {R_E^3}}$$

$$1 + {r \over {{R_E}}} + {{{r^2}} \over {R_E^2}} + {{{r^3}} \over {R_E^3}}$$

$$1 + {r \over {{R_E}}} - {{{r^2}} \over {R_E^2}} + {{{r^3}} \over {R_E^3}}$$

$$1 + {r \over {{R_E}}} - {{{r^2}} \over {R_E^2}} - {{{r^3}} \over {R_E^3}}$$

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