AIEEE 2004 | Gravitation Question 174 | Physics

Suppose the gravitational force varies inversely as the n^th power of distance. Then the time period of a planet in circular orbit of radius $$R$$ around the sun will be proportional to

$${R^n}$$

$${R^{\left( {{{n - 1} \over 2}} \right)}}$$

$${R^{\left( {{{n + 1} \over 2}} \right)}}$$

$${R^{\left( {{{n - 2} \over 2}} \right)}}$$

AIEEE 2003

MCQ (Single Correct Answer)

-1

The time period of satellite of earth is $$5$$ hours. If the separation between the earth and the satellite is increased to $$4$$ times the previous value, the new time period will become

$$10$$ hours

$$80$$ hours

$$40$$ hours

$$20$$ hours

AIEEE 2003

MCQ (Single Correct Answer)

-1

The escape velocity for a body projected vertically upwards from the surface of earth is $$11$$ $$km/s.$$ If the body is projected at an angle of $${45^ \circ }$$ with the vertical, the escape velocity will be

$$11\sqrt 2 \,\,km/s$$

$$22$$ $$km/s$$

$$11$$ $$km/s$$

$${{11} \over {\sqrt 2 }}km/s$$

AIEEE 2003

MCQ (Single Correct Answer)

-1

Two spherical bodies of mass $$M$$ and $$5M$$ & radii $$R$$ & $$2R$$ respectively are released in free space with initial separation between their centers equal to $$12R$$. If they attract each other due to gravitational force only, then the distance covered by the smaller body just before collision is

$$2.5$$ $$R$$

$$4.5$$ $$R$$

$$7.5$$ $$R$$

$$1.5$$ $$R$$

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