JEE Main 2021 (Online) 25th February Morning Shift | Alternating Current Question 74 | Physics

JEE Main 2021 (Online) 25th February Morning Shift

MCQ (Single Correct Answer)

-1

The current (i) at time t = 0 and t = $$\infty $$ respectively for the given circuit is :

JEE Main 2021 (Online) 25th February Morning Shift Physics - Alternating Current Question 74 English

JEE Main 2021 (Online) 25th February Morning Shift Physics - Alternating Current Question 74 English

$${{18E} \over {55}},{{5E} \over {18}}$$

$${{5E} \over {18}},{{18E} \over {55}}$$

$${{5E} \over {18}},{{10E} \over {33}}$$

$${{10E} \over {33}},{{5E} \over {18}}$$

JEE Main 2020 (Online) 6th September Morning Slot

MCQ (Single Correct Answer)

-1

An AC circuit has R= 100 $$\Omega $$, C = 2 $$\mu $$F and L = 80 mH, connected in series. The quality factor of the circuit is :

0.5

400

JEE Main 2020 (Online) 4th September Evening Slot

MCQ (Single Correct Answer)

-1

A series L-R circuit is connected to a battery of emf V. If the circuit is switched on at t = 0, then the time at which the energy stored in the inductor reaches $$\left( {{1 \over n}} \right)$$ times of its maximum value, is :

$${L \over R}\ln \left( {{{\sqrt n } \over {\sqrt n + 1}}} \right)$$

$${L \over R}\ln \left( {{{\sqrt n } \over {\sqrt n - 1}}} \right)$$

$${L \over R}\ln \left( {{{\sqrt n + 1} \over {\sqrt n - 1}}} \right)$$

$${L \over R}\ln \left( {{{\sqrt n - 1} \over {\sqrt n }}} \right)$$

JEE Main 2020 (Online) 2nd September Evening Slot

MCQ (Single Correct Answer)

-1

An inductance coil has a reactance of 100 $$\Omega $$. When an AC signal of frequency 1000 Hz is applied to the coil, the applied voltage leads the current by 45^o. The self-inductance of the coil is

6.7 $$ \times $$ 10^–7 H

1.1 $$ \times $$ 10^–1 H

5.5 $$ \times $$ 10^–5 H

1.1 $$ \times $$ 10^–2 H

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