1
JEE Main 2016 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
An arc lamp requires a direct current of 10 A at 80 V to function. If it is connected to a 220 V (rms), 50 Hz AC supply, the series inductor needed for it to work is close to :
A
0.044 H
B
0.065 H
C
80 H
D
0.08 H
2
JEE Main 2015 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language

An $$LCR$$ circuit is equivalent to a damped pendulum. In an $$LCR$$ circuit the capacitor is charged to $${Q_0}$$ and then connected to the $$L$$ and $$R$$ as shown below :

JEE Main 2015 (Offline) Physics - Alternating Current Question 144 English

If a student plots graphs of the square of maximum charge $$\left( {Q_{Max}^2} \right)$$ on the capacitor with time$$(t)$$ for two different values $${L_1}$$ and $${L_2}$$ $$\left( {{L_1} > {L_2}} \right)$$ of $$L$$ then which of the following represents this graph correctly ?
$$\left( {plots\,\,are\,\,schematic\,\,and\,\,niot\,\,drawn\,\,to\,\,scale} \right)$$

A
JEE Main 2015 (Offline) Physics - Alternating Current Question 144 English Option 1
B
JEE Main 2015 (Offline) Physics - Alternating Current Question 144 English Option 2
C
JEE Main 2015 (Offline) Physics - Alternating Current Question 144 English Option 3
D
JEE Main 2015 (Offline) Physics - Alternating Current Question 144 English Option 4
3
JEE Main 2015 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
An inductor $$(L=0.03$$ $$H)$$ and a resistor $$\left( {R = 0.15\,k\Omega } \right)$$ are connected in series to a battery of $$15V$$ $$EMF$$ in a circuit shown below. The key $${K_1}$$ has been kept closed for a long time. Then at $$t=0$$, $${K_1}$$ is opened and key $${K_2}$$ is closed simultaneously. At $$t=1$$ $$ms,$$ the current in the circuit will be : $$\left( {{e^5} \cong 150} \right)$$

JEE Main 2015 (Offline) Physics - Alternating Current Question 145 English
A
$$6.7$$ $$mA$$
B
$$0.67$$ $$mA$$
C
$$100$$ $$mA$$
D
$$67$$ $$mA$$
4
JEE Main 2014 (Offline)
MCQ (Single Correct Answer)
+4
-1
In the circuit shown here, the point $$'C'$$ is kept connected to point $$'A'$$ till the current flowing through the circuit becomes constant. Afterward, suddenly, point $$'C'$$ is disconnected from point $$'A'$$ and connected to point $$'B'$$ at time $$t=0.$$ Ratio of the voltage across resistance and the inductor at $$t=L/R$$ will be equal to : JEE Main 2014 (Offline) Physics - Alternating Current Question 146 English
A
$${e \over {1 - e}}$$
B
$$1$$
C
$$-1$$
D
$${{1 - e} \over e}$$
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