JEE Main 2024 (Online) 1st February Morning Shift | Alternating Current Question 15 | Physics

A parallel plate capacitor has a capacitance $\mathrm{C}=200~ \mathrm{pF}$. It is connected to $230 \mathrm{~V}$ ac supply with an angular frequency $300~ \mathrm{rad} / \mathrm{s}$. The rms value of conduction current in the circuit and displacement current in the capacitor respectively are :

$14.3 ~\mu \mathrm{A}$ and $143 ~\mu \mathrm{A}$

$13.8 ~\mu \mathrm{A}$ and $13.8 ~\mu \mathrm{A}$

$13.8 ~\mu \mathrm{A}$ and $138 ~\mu \mathrm{A}$

$1.38 ~\mu \mathrm{A}$ and $1.38 ~\mu \mathrm{A}$

JEE Main 2024 (Online) 1st February Morning Shift

MCQ (Single Correct Answer)

-1

In series LCR circuit, the capacitance is changed from $C$ to $4 C$. To keep the resonance frequency unchanged, the new inductance should be:

increased by $2 \mathrm{~L}$

reduced by $\frac{1}{4} \mathrm{~L}$

reduced by $\frac{3}{4} \mathrm{~L}$

increased to $4 \mathrm{~L}$

JEE Main 2024 (Online) 31st January Evening Shift

MCQ (Single Correct Answer)

-1

An AC voltage $$V=20 \sin 200 \pi t$$ is applied to a series LCR circuit which drives a current $$I=10 \sin \left(200 \pi t+\frac{\pi}{3}\right)$$. The average power dissipated is:

21.6 W

200 W

173.2 W

50 W

JEE Main 2024 (Online) 30th January Evening Shift

MCQ (Single Correct Answer)

-1

An alternating voltage $$V(t)=220 \sin 100 \pi t$$ volt is applied to a purely resistive load of $$50 \Omega$$. The time taken for the current to rise from half of the peak value to the peak value is:

7.2 ms

3.3 ms

5 ms

2.2 ms

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