1
JEE Main 2024 (Online) 4th April Evening Shift
+4
-1

Match List I with List II

LIST I LIST II
A. Purely capacitive circuit I.
B. Purely inductive circuit II.
C. LCR series at resonance III.
D. LCR series circuit IV.

Choose the correct answer from the options given below:

A
A-IV. B-I, C-III, D-II
B
A-I. B-IV, C-II, D-III
C
A-IV. B-I, C-II, D-III
D
A-I. B-IV, C-III, D-II
2
JEE Main 2024 (Online) 4th April Morning Shift
+4
-1

In an ac circuit, the instantaneous current is zero, when the instantaneous voltage is maximum. In this case, the source may be connected to :

A. pure inductor.

B. pure capacitor.

C. pure resistor.

D. combination of an inductor and capacitor.

Choose the correct answer from the options given below :

A
A, B and C only
B
A and B only
C
A, B and D only
D
B, C and D only
3
JEE Main 2024 (Online) 1st February Morning Shift
+4
-1
A parallel plate capacitor has a capacitance $\mathrm{C}=200~ \mathrm{pF}$. It is connected to $230 \mathrm{~V}$ ac supply with an angular frequency $300~ \mathrm{rad} / \mathrm{s}$. The rms value of conduction current in the circuit and displacement current in the capacitor respectively are :
A
$14.3 ~\mu \mathrm{A}$ and $143 ~\mu \mathrm{A}$
B
$13.8 ~\mu \mathrm{A}$ and $13.8 ~\mu \mathrm{A}$
C
$13.8 ~\mu \mathrm{A}$ and $138 ~\mu \mathrm{A}$
D
$1.38 ~\mu \mathrm{A}$ and $1.38 ~\mu \mathrm{A}$
4
JEE Main 2024 (Online) 1st February Morning Shift
+4
-1
In series LCR circuit, the capacitance is changed from $C$ to $4 C$. To keep the resonance frequency unchanged, the new inductance should be:
A
increased by $2 \mathrm{~L}$
B
reduced by $\frac{1}{4} \mathrm{~L}$
C
reduced by $\frac{3}{4} \mathrm{~L}$
D
increased to $4 \mathrm{~L}$
EXAM MAP
Medical
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