AIEEE 2004 | Gravitation Question 177 | Physics

A satellite of mass $$m$$ revolves around the earth of radius $$R$$ at a height $$x$$ from its surface. If $$g$$ is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is

$${{g{R^2}} \over {R + x}}$$

$${{gR} \over {R - x}}$$

$${gx}$$

$${\left( {{{g{R^2}} \over {R + x}}} \right)^{1/2}}$$

AIEEE 2004

MCQ (Single Correct Answer)

-1

If $$g$$ is the acceleration due to gravity on the earth's surface, the gain in the potential energy of an object of mass $$m$$ raised from the surface of the earth to a height equal to the radius $$R$$ of the earth is

$${1 \over 4}mgR$$

$$2mgR$$

$${1 \over 2}mgR$$

$$mgR$$

AIEEE 2004

MCQ (Single Correct Answer)

-1

The time period of an earth satellite in circular orbit is independent of

both the mass and radius of the orbit

radius of its orbit

the mass of the satellite

neither the mass of the satellite nor the radius of its orbit

AIEEE 2004

MCQ (Single Correct Answer)

-1

Suppose the gravitational force varies inversely as the n^th power of distance. Then the time period of a planet in circular orbit of radius $$R$$ around the sun will be proportional to

$${R^n}$$

$${R^{\left( {{{n - 1} \over 2}} \right)}}$$

$${R^{\left( {{{n + 1} \over 2}} \right)}}$$

$${R^{\left( {{{n - 2} \over 2}} \right)}}$$

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