JEE Main 2024 (Online) 5th April Morning Shift | Gravitation Question 10 | Physics

	LIST I		LIST II
A.	Kinetic energy of planet	I.	$$ -\mathrm{GMm} / \mathrm{a} $$
B.	Gravitation Potential energy of sun-planet system	II.	$$ \mathrm{GMm} / 2 \mathrm{a} $$
C.	Total mechanical energy of planet	III.	$$ \frac{\mathrm{Gm}}{\mathrm{r}} $$
D.	Escape energy at the surface of planet for unit mass object	IV.	$$ -\mathrm{GMm} / 2 \mathrm{a} $$

(Where $$\mathrm{a}=$$ radius of planet orbit, $$\mathrm{r}=$$ radius of planet, $$\mathrm{M}=$$ mass of Sun, $$\mathrm{m}=$$ mass of planet)

Choose the correct answer from the options given below :

(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

(A)-(I), (B)-(IV), (C)-(II), (D)-(III)

JEE Main 2024 (Online) 4th April Evening Shift

MCQ (Single Correct Answer)

-1

A $$90 \mathrm{~kg}$$ body placed at $$2 \mathrm{R}$$ distance from surface of earth experiences gravitational pull of :

($$\mathrm{R}=$$ Radius of earth, $$\mathrm{g}=10 \mathrm{~m} \mathrm{~s}^{-2}$$)

300 N

225 N

100 N

120 N

JEE Main 2024 (Online) 4th April Evening Shift

MCQ (Single Correct Answer)

-1

Correct formula for height of a satellite from earths surface is :

$$\left(\frac{T^2 R^2 g}{4 \pi^2}\right)^{1 / 3}-R$$

$$\left(\frac{T^2 R^2 g}{4 \pi}\right)^{1 / 2}-R$$

$$\left(\frac{T^2 R^2 g}{4 \pi^2}\right)^{-1 / 3}+R$$

$$\left(\frac{T^2 R^2}{4 \pi^2 g}\right)^{1 / 3}-R$$

JEE Main 2024 (Online) 4th April Morning Shift

MCQ (Single Correct Answer)

-1

A metal wire of uniform mass density having length $$L$$ and mass $$M$$ is bent to form a semicircular arc and a particle of mass $$\mathrm{m}$$ is placed at the centre of the arc. The gravitational force on the particle by the wire is :

$$\frac{\mathrm{GmM} \pi^2}{\mathrm{~L}^2}$$

$$\frac{\mathrm{GMm} \pi}{2 \mathrm{~L}^2}$$

$$\frac{2 \mathrm{GmM} \pi}{\mathrm{L}^2}$$

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Questions Asked from Gravitation (MCQ (Single Correct Answer))

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