1
JEE Main 2022 (Online) 29th July Evening Shift
+4
-1
Out of Syllabus

The vertical component of the earth's magnetic field is $$6 \times 10^{-5} \mathrm{~T}$$ at any place where the angle of dip is $$37^{\circ}$$. The earth's resultant magnetic field at that place will be $$\left(\right.$$Given $$\left.\tan 37^{\circ}=\frac{3}{4}\right)$$

A
$$8 \times 10^{-5} \mathrm{~T}$$
B
$$6 \times 10^{-5} \mathrm{~T}$$
C
$$5 \times 10^{-4} \mathrm{~T}$$
D
$$1 \times 10^{-4} \mathrm{~T}$$
2
JEE Main 2022 (Online) 27th July Evening Shift
+4
-1
Out of Syllabus

A compass needle of oscillation magnetometer oscillates 20 times per minute at a place $$\mathrm{P}$$ of $$\operatorname{dip} 30^{\circ}$$. The number of oscillations per minute become 10 at another place $$\mathrm{Q}$$ of $$60^{\circ}$$ dip. The ratio of the total magnetic field at the two places $$\left(B_{Q}: B_{P}\right)$$ is :

A
$$\sqrt{3}: 4$$
B
$$4: \sqrt{3}$$
C
$$\sqrt{3}: 2$$
D
$$2: \sqrt{3}$$
3
JEE Main 2022 (Online) 27th July Morning Shift
+4
-1
Out of Syllabus

Two bar magnets oscillate in a horizontal plane in earth's magnetic field with time periods of $$3 \mathrm{~s}$$ and $$4 \mathrm{~s}$$ respectively. If their moments of inertia are in the ratio of $$3: 2$$, then the ratio of their magnetic moments will be:

A
2 : 1
B
8 : 3
C
1 : 3
D
27 : 16
4
JEE Main 2022 (Online) 27th July Morning Shift
+4
-1
Out of Syllabus

A magnet hung at $$45^{\circ}$$ with magnetic meridian makes an angle of $$60^{\circ}$$ with the horizontal. The actual value of the angle of dip is -

A
$$\tan ^{-1}\left(\sqrt{\frac{3}{2}}\right)$$
B
$$\tan ^{-1}(\sqrt{6})$$
C
$$\tan ^{-1}\left(\sqrt{\frac{2}{3}}\right)$$
D
$$\tan ^{-1}\left(\sqrt{\frac{1}{2}}\right)$$
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