1
JEE Main 2019 (Online) 8th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Two magnetic dipoles X and Y are placed at a separation d, with their axes perpendicular to each other. The dipole moment of Y is twice that of X. A particle of charge q is passing, through their midpoint P, at angle q = 45° with the horizontal line, as shown in figure. What would be the magnitude of force on the particle at that instant ?
(d is much larger than the dimensions of the dipole) JEE Main 2019 (Online) 8th April Evening Slot Physics - Magnetic Properties of Matter Question 45 English
A
$$ \left( {{{{\mu _0}} \over {4\pi }}} \right){2M \over {{{\left( {d/2} \right)}^3}}} \times qv$$
B
$$ \left( {{{{\mu _0}} \over {4\pi }}} \right){M \over {{{\left( {d/2} \right)}^3}}} \times qv$$
C
$$\sqrt 2 \left( {{{{\mu _0}} \over {4\pi }}} \right){M \over {{{\left( {d/2} \right)}^3}}} \times qv$$
D
0
2
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A paramagnetic material has 1028 atoms/m3. Its magnetic susceptibility at temperature 350 K is 2.8 $$ \times $$ 10–4. Its susceptibility at 300 K is :
A
3.726 $$ \times $$ 10–4
B
2.672 $$ \times $$ 10–4
C
3.672 $$ \times $$ 10–4
D
3.267 $$ \times $$ 10$$-$$4
3
JEE Main 2019 (Online) 11th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20 $$ \times $$ 10–6 J/ T when a magnetic intensity of 60 $$ \times $$ 103 A/m is applied. Its magnetic susceptibility is
A
3.3 $$ \times $$ 10–4
B
2.3 $$ \times $$ 10–2
C
4.3 $$ \times $$ 10–2
D
3.3 $$ \times $$ 10–2
4
JEE Main 2019 (Online) 10th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
At some location on earth, the horizontal component of earth’s magnetic field is 18 × 10–6 T. At this location, magnetic needle of length 0.12 m and pole strength 1.8 Am is suspended from its mid-point using a thread, it makes 45o angle with horizontal in equilibrium. To keep this needle horizontal, the vertical force that should be applied at one of its ends is -
A
3.6 $$ \times $$ 10$$-$$5 N
B
1.8 $$ \times $$ 10$$-$$5 N
C
1.3 $$ \times $$ 10$$-$$5 N
D
6.5 $$ \times $$ 10$$-$$5 N
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