1
JEE Main 2019 (Online) 10th January Evening Slot
+4
-1
At some location on earth the horizontal component of earth’s magnetic field is 18 × 10–6 T. At this location, magnetic needle of length 0.12 m and pole strength 1.8 Am is suspended from its mid-point using a thread, it makes 45o angle with horizontal in equilibrium. To keep this needle horizontal, the vertical force that should be applied at one of its ends is -
A
3.6 $$\times$$ 10$$-$$5 N
B
1.8 $$\times$$ 10$$-$$5 N
C
1.3 $$\times$$ 10$$-$$5 N
D
6.5 $$\times$$ 10$$-$$5 N
2
JEE Main 2019 (Online) 10th January Evening Slot
+4
-1
A hoop and a solid cylinder of same mass and radius are made of a permanent magnetic material with their magnetic moment parallel to their respective axes. But the magnetic moment of hoop is twice of solid cylinder. They are placed in a uniform magnetic field in such a manner that their magnetic moments make a small angle with the field. If the oscillation periods of hoop and cylinder are Th and Tc respectively, then -
A
Th = 1.5 Tc
B
Th = Tc
C
Th = 2Tc
D
Th = 0.5 Tc
3
JEE Main 2019 (Online) 10th January Morning Slot
+4
-1
A magnet of total magnetic moment 10-2$${\widehat i}$$A-m2 is placed in a time varying magnetic field, B$${\widehat i}$$ (co where B = 1 Tesla and $$\omega$$ = 0.125 rad/s. The work done for reversing the direction of the magnetic moment at t = 1 second, is -
A
0.014 J
B
0.028 J
C
0.01 J
D
0.007 J
4
JEE Main 2019 (Online) 10th January Morning Slot
+4
-1
A solid metal cube of edge length 2 cm is moving in a positive y-direction at a constant speed of 6 m/s. There is a uniform magnetic field of 0.1 T in the positive z-direction. The potential difference between the two faces of the cube perpendicular to the x-axis, is -
A
2mV
B
12 mV
C
6 mV
D
1 mV
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