JEE Main 2026 (Online) 2nd April Morning Shift

MCQ (Single Correct Answer)

-1

The velocity of a particle is given as $\vec{v} = -x \hat{i} + 2y \hat{j} - z \hat{k}$ m/s. The magnitude of acceleration at point (1, 2, 4) is ________ m/s².

$\sqrt{6}$

$9$

$\sqrt{33}$

$0$

JEE Main 2024 (Online) 5th April Morning Shift

MCQ (Single Correct Answer)

-1

The angle between vector $$\vec{Q}$$ and the resultant of $$(2 \vec{Q}+2 \vec{P})$$ and $$(2 \vec{Q}-2 \vec{P})$$ is :

$$ \tan ^{-1}(\mathrm{P} / \mathrm{Q}) $$

0$$^\circ$$

$$ \tan ^{-1} \frac{(2 \vec{Q}-2 \vec{P})}{2 \vec{Q}+2 \vec{P}} $$

$$ \tan ^{-1}(2 Q / \mathrm{P}) $$

JEE Main 2024 (Online) 31st January Evening Shift

MCQ (Single Correct Answer)

-1

If two vectors $$\vec{A}$$ and $$\vec{B}$$ having equal magnitude $$R$$ are inclined at angle $$\theta$$, then

$$|\vec{A}+\vec{B}|=2 R \cos \left(\frac{\theta}{2}\right)$$

$$|\vec{A}-\vec{B}|=2 R \cos \left(\frac{\theta}{2}\right)$$

$$|\vec{A}-\vec{B}|=\sqrt{2} R \sin \left(\frac{\theta}{2}\right)$$

$$|\vec{A}+\vec{B}|=2 R \sin \left(\frac{\theta}{2}\right)$$

JEE Main 2023 (Online) 15th April Morning Shift

MCQ (Single Correct Answer)

-1

A vector in $x-y$ plane makes an angle of $30^{\circ}$ with $y$-axis. The magnitude of $\mathrm{y}$-component of vector is $2 \sqrt{3}$. The magnitude of $x$-component of the vector will be :

$\sqrt{3}$

$\frac{1}{\sqrt{3}}$

JEE Main Subjects

Browse all chapters by subject