1
JEE Main 2024 (Online) 31st January Evening Shift
+4
-1

If two vectors $$\vec{A}$$ and $$\vec{B}$$ having equal magnitude $$R$$ are inclined at angle $$\theta$$, then

A
$$|\vec{A}+\vec{B}|=2 R \cos \left(\frac{\theta}{2}\right)$$
B
$$|\vec{A}-\vec{B}|=2 R \cos \left(\frac{\theta}{2}\right)$$
C
$$|\vec{A}-\vec{B}|=\sqrt{2} R \sin \left(\frac{\theta}{2}\right)$$
D
$$|\vec{A}+\vec{B}|=2 R \sin \left(\frac{\theta}{2}\right)$$
2
JEE Main 2023 (Online) 15th April Morning Shift
+4
-1
A vector in $x-y$ plane makes an angle of $30^{\circ}$ with $y$-axis. The magnitude of $\mathrm{y}$-component of vector is $2 \sqrt{3}$. The magnitude of $x$-component of the vector will be :
A
$\sqrt{3}$
B
2
C
6
D
$\frac{1}{\sqrt{3}}$
3
JEE Main 2023 (Online) 11th April Evening Shift
+4
-1

When vector $$\vec{A}=2 \hat{i}+3 \hat{j}+2 \hat{k}$$ is subtracted from vector $$\overrightarrow{\mathrm{B}}$$, it gives a vector equal to $$2 \hat{j}$$. Then the magnitude of vector $$\overrightarrow{\mathrm{B}}$$ will be :

A
3
B
$$\sqrt{33}$$
C
$$\sqrt6$$
D
$$\sqrt5$$
4
JEE Main 2023 (Online) 8th April Morning Shift
+4
-1

Two forces having magnitude $$A$$ and $$\frac{A}{2}$$ are perpendicular to each other. The magnitude of their resultant is:

A
$$\frac{5 A}{2}$$
B
$$\frac{\sqrt{5} A}{4}$$
C
$$\frac{\sqrt{5} A}{2}$$
D
$$\frac{\sqrt{5} A^{2}}{2}$$
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