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JEE Main 2024 (Online) 8th April Evening Shift
Numerical
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If the net electric field at point $$\mathrm{P}$$ along $$\mathrm{Y}$$ axis is zero, then the ratio of $$\left|\frac{q_2}{q_3}\right|$$ is $$\frac{8}{5 \sqrt{x}}$$, where $$x=$$ ________.

JEE Main 2024 (Online) 8th April Evening Shift Physics - Electrostatics Question 46 English

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2
JEE Main 2024 (Online) 8th April Morning Shift
Numerical
+4
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An electric field, $$\overrightarrow{\mathrm{E}}=\frac{2 \hat{i}+6 \hat{j}+8 \hat{k}}{\sqrt{6}}$$ passes through the surface of $$4 \mathrm{~m}^2$$ area having unit vector $$\hat{n}=\left(\frac{2 \hat{i}+\hat{j}+\hat{k}}{\sqrt{6}}\right)$$. The electric flux for that surface is _________ $$\mathrm{Vm}$$.

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3
JEE Main 2024 (Online) 6th April Morning Shift
Numerical
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-1
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Three infinitely long charged thin sheets are placed as shown in figure. The magnitude of electric field at the point $$P$$ is $$\frac{x \sigma}{\epsilon_0}$$. The value of $$x$$ is _________ (all quantities are measured in SI units).

JEE Main 2024 (Online) 6th April Morning Shift Physics - Electrostatics Question 38 English

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4
JEE Main 2024 (Online) 5th April Evening Shift
Numerical
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-1
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The electric field at point $$\mathrm{p}$$ due to an electric dipole is $$\mathrm{E}$$. The electric field at point $$\mathrm{R}$$ on equitorial line will be $$\frac{\mathrm{E}}{x}$$. The value of $$x$$ :

JEE Main 2024 (Online) 5th April Evening Shift Physics - Electrostatics Question 41 English

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