JEE Main 2022 (Online) 27th June Evening Shift | Waves Question 52 | Physics

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JEE Main 2022 (Online) 27th June Evening Shift

MCQ (Single Correct Answer)

-1

If a wave gets refracted into a denser medium, then which of the following is true?

wavelength, speed and frequency decreases.

wavelength increases, sped decreases and frequency remains constant.

wavelength and speed decreases but frequency remains constant.

wavelength, speed and frequency increases.

JEE Main 2022 (Online) 27th June Morning Shift

MCQ (Single Correct Answer)

-1

Out of Syllabus

An observer moves towards a stationary source of sound with a velocity equal to one-fifth of the velocity of sound. The percentage change in the frequency will be :

20%

10%

JEE Main 2022 (Online) 24th June Morning Shift

MCQ (Single Correct Answer)

-1

The equations of two waves are given by :

y₁ = 5 sin 2$$\pi$$(x - vt) cm

y₂ = 3 sin 2$$\pi$$(x $$-$$ vt + 1.5) cm

These waves are simultaneously passing through a string. The amplitude of the resulting wave is :

2 cm

4 cm

5.8 cm

8 cm

JEE Main 2021 (Online) 22th July Evening Shift

MCQ (Single Correct Answer)

-1

The motion of a mass on a spring, with spring constant K is as shown in figure.

JEE Main 2021 (Online) 22th July Evening Shift Physics - Waves Question 64 English

JEE Main 2021 (Online) 22th July Evening Shift Physics - Waves Question 64 English

The equation of motion is given by
x(t) = A sin$$\omega$$t + B cos$$\omega$$t with $$\omega$$ = $$\sqrt {{K \over m}} $$

Suppose that at time t = 0, the position of mass is x(0) and velocity v(0), then its displacement can also be represented as x(t) = C cos($$\omega$$t $$-$$ $$\phi$$), where C and $$\phi$$ are :

$$C = \sqrt {{{2v{{(0)}^2}} \over {{\omega ^2}}} + x{{(0)}^2}} ,\phi = {\tan ^{ - 1}}\left( {{{x(0)\omega } \over {2v(0)}}} \right)$$

$$C = \sqrt {{{v{{(0)}^2}} \over {{\omega ^2}}} + x{{(0)}^2}} ,\phi = {\tan ^{ - 1}}\left( {{{x(0)\omega } \over {v(0)}}} \right)$$

$$C = \sqrt {{{v{{(0)}^2}} \over {{\omega ^2}}} + x{{(0)}^2}} ,\phi = {\tan ^{ - 1}}\left( {{{v(0)} \over {x(0)\omega }}} \right)$$

$$C = \sqrt {{{2v{{(0)}^2}} \over {{\omega ^2}}} + x{{(0)}^2}} ,\phi = {\tan ^{ - 1}}\left( {{{v(0)} \over {x(0)\omega }}} \right)$$

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