JEE Main 2019 (Online) 9th April Evening Slot | Center of Mass and Collision Question 80 | Physics

A wedge of mass M = 4m lies on a frictionless plane. A particle of mass m approaches the wedge with speed v. There is no friction between the particle and the plane or between the particle and the wedge. The maximum height climbed by the particle on the wedge is given by :-

$${{{v^2}} \over {g}}$$

$${{2{v^2}} \over {7g}}$$

$${{{v^2}} \over {2g}}$$

$${{2{v^2}} \over {5g}}$$

JEE Main 2019 (Online) 9th April Evening Slot

MCQ (Single Correct Answer)

-1

A particle of mass 'm' is moving with speed '2v' and collides with a mass '2m' moving with speed 'v' in the same direction. After collision, the first mass is stopped completely while the second one splits into two particles each of mass 'm', which move at angle 45° with respect to the origianl direction. The speed of each of the moving particle will be :-

2 $$\sqrt2$$v

v / (2 $$\sqrt2$$ )

v / $$\sqrt2$$

$$\sqrt2$$v

JEE Main 2019 (Online) 9th April Morning Slot

MCQ (Single Correct Answer)

-1

A ball is thrown vertically up (taken as +z-axis) from the ground. The correct momentum-height (p-h) diagram is :

JEE Main 2019 (Online) 9th April Morning Slot Physics - Center of Mass and Collision Question 82 English Option 1

JEE Main 2019 (Online) 9th April Morning Slot Physics - Center of Mass and Collision Question 82 English Option 2

JEE Main 2019 (Online) 9th April Morning Slot

MCQ (Single Correct Answer)

-1

A body of mass 2 kg makes an eleastic collision with a second body at rest and continues to move in the original direction but with one fourth of its original speed. What is the mass of the second body ?

1.2 kg

1.0 kg

1.8 kg

1.5 kg

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