JEE Main 2023 (Online) 31st January Evening Shift | Circular Motion Question 18 | Physics

JEE Main 2023 (Online) 31st January Evening Shift

MCQ (Single Correct Answer)

-1

A stone of mass $1 \mathrm{~kg}$ is tied to end of a massless string of length $1 \mathrm{~m}$. If the breaking tension of the string is $400 \mathrm{~N}$, then maximum linear velocity, the stone can have without breaking the string, while rotating in horizontal plane, is :

$20 \mathrm{~ms}^{-1}$

$40 \mathrm{~ms}^{-1}$

$400 \mathrm{~ms}^{-1}$

$10 \mathrm{~ms}^{-1}$

JEE Main 2023 (Online) 31st January Evening Shift

MCQ (Single Correct Answer)

-1

A body is moving with constant speed, in a circle of radius $10 \mathrm{~m}$. The body completes one revolution in $4 \mathrm{~s}$. At the end of 3rd second, the displacement of body (in $\mathrm{m}$ ) from its starting point is :

$15 \pi$

$10 \sqrt{2}$

$5 \pi$

JEE Main 2023 (Online) 29th January Evening Shift

MCQ (Single Correct Answer)

-1

An object moves at a constant speed along a circular path in a horizontal plane with center at the origin. When the object is at $$x=+2~\mathrm{m}$$, its velocity is $$\mathrm{ - 4\widehat j}$$ m/s. The object's velocity (v) and acceleration (a) at $$x=-2~\mathrm{m}$$ will be

$$v=4\mathrm{\widehat i~m/s},a=8\mathrm{\widehat j~m/s^2}$$

$$v=4\mathrm{\widehat j~m/s},a=8\mathrm{\widehat i~m/s^2}$$

$$v=-4\mathrm{\widehat i~m/s},a=-8\mathrm{\widehat j~m/s^2}$$

$$v=-4\mathrm{\widehat j~m/s},a=8\mathrm{\widehat i~m/s^2}$$

JEE Main 2023 (Online) 29th January Morning Shift

MCQ (Single Correct Answer)

-1

A car is moving on a horizontal curved road with radius 50 m. The approximate maximum speed of car will be, if friction between tyres and road is 0.34. [take g = 10 ms$$^{-2}$$]

3.4 ms$$^{-1}$$

13 ms$$^{-1}$$

22.4 ms$$^{-1}$$

17 ms$$^{-1}$$

PREVIOUS NEXT

JEE Main Subjects