JEE Main 2021 (Online) 26th February Morning Shift | Circular Motion Question 46 | Physics

JEE Main 2021 (Online) 26th February Morning Shift

MCQ (Single Correct Answer)

-1

A particle is moving with uniform speed along the circumference of a circle of radius R under the action of a central fictitious force F which is inversely proportional to R³. Its time period of revolution will be given by :

$$T \propto {R^{{4 \over 3}}}$$

$$T \propto {R^{{5 \over 2}}}$$

$$T \propto {R^{{3 \over 2}}}$$

$$T \propto {R^2}$$

JEE Main 2020 (Online) 6th September Morning Slot

MCQ (Single Correct Answer)

-1

A clock has a continuously moving second's hand of 0.1 m length. The average acceleration of the tip of the hand (in units of ms^–2) is of the order of :

10^-3

10^-1

10^-2

10^-4

JEE Main 2020 (Online) 2nd September Morning Slot

MCQ (Single Correct Answer)

-1

A bead of mass m stays at point P(a, b) on a wire bent in the shape of a parabola y = 4Cx² and rotating with angular speed $$\omega $$ (see figure). The value of $$\omega $$ is (neglect friction) : JEE Main 2020 (Online) 2nd September Morning Slot Physics - Circular Motion Question 49 English

JEE Main 2020 (Online) 2nd September Morning Slot Physics - Circular Motion Question 49 English

$$2\sqrt {2gC} $$

$$2\sqrt {gC} $$

$$\sqrt {{{2gC} \over {ab}}} $$

$$\sqrt {{{2g} \over C}} $$

JEE Main 2020 (Online) 8th January Morning Slot

MCQ (Single Correct Answer)

-1

A particle of mass m is fixed to one end of a light spring having force constant k and unstretched length $$\ell $$. The other end is fixed. The system is given an angular speed $$\omega $$ about the fixed end of the spring such that it rotates in a circle in gravity free space. Then the stretch in the spring is :

$${{m\ell {\omega ^2}} \over {k - m{\omega ^2}}}$$

$${{m\ell {\omega ^2}} \over {k - m{\omega}}}$$

$${{m\ell {\omega ^2}} \over {k + m{\omega ^2}}}$$

$${{m\ell {\omega ^2}} \over {k + m{\omega}}}$$

PREVIOUS NEXT

JEE Main Subjects