JEE Main 2021 (Online) 17th March Morning Shift | Circular Motion Question 52 | Physics

JEE Main 2021 (Online) 17th March Morning Shift

MCQ (Single Correct Answer)

-1

A modern grand - prix racing car of mass m is travelling on a flat track in a circular arc of radius R with a speed v. If the coefficient of static friction between the tyres and the track is $$\mu$$_s, then the magnitude of negative lift F_L acting downwards on the car is : (Assume forces on the four tyres are identical and g = acceleration due to gravity)

JEE Main 2021 (Online) 17th March Morning Shift Physics - Circular Motion Question 52 English

JEE Main 2021 (Online) 17th March Morning Shift Physics - Circular Motion Question 52 English

$$m\left( {g - {{{v^2}} \over {{\mu _s}R}}} \right)$$

$$ - m\left( {g + {{{v^2}} \over {{\mu _s}R}}} \right)$$

$$m\left( {{{{v^2}} \over {{\mu _s}R}} - g} \right)$$

$$m\left( {{{{v^2}} \over {{\mu _s}R}} + g} \right)$$

JEE Main 2021 (Online) 16th March Evening Shift

MCQ (Single Correct Answer)

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Statement I : A cyclist is moving on an unbanked road with a speed of 7 kmh^$$-$$1 and takes a sharp circular turn along a path of radius of 2m without reducing the speed. The static friction coefficient is 0.2. The cyclist will not slip and pass the curve. (g = 9.8 m/s²)

Statement II : If the road is banked at an angle of 45$$^\circ$$, cyclist can cross the curve of 2m radius with the speed of 18.5 kmh^$$-$$1 without slipping.

In the light of the above statements, choose the correct answer from the options given below.

Statement I is incorrect and statement II is correct

Both statement I and statement II are true

Statement I is correct and statement II is incorrect

Both statement I and statement II are false

JEE Main 2021 (Online) 16th March Morning Shift

MCQ (Single Correct Answer)

-1

A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is :

9.859 $$\times$$ 10^$$-$$2 N

0.0314 N

9.859 $$\times$$ 10^$$-$$4 N

6.28 $$\times$$ 10^$$-$$3 N

JEE Main 2021 (Online) 26th February Morning Shift

MCQ (Single Correct Answer)

-1

A particle is moving with uniform speed along the circumference of a circle of radius R under the action of a central fictitious force F which is inversely proportional to R³. Its time period of revolution will be given by :

$$T \propto {R^{{4 \over 3}}}$$

$$T \propto {R^{{5 \over 2}}}$$

$$T \propto {R^{{3 \over 2}}}$$

$$T \propto {R^2}$$

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