JEE Main 2019 (Online) 11th January Morning Slot | Rotational Motion Question 123 | Physics

JEE Main 2019 (Online) 11th January Morning Slot

MCQ (Single Correct Answer)

-1

A particle is moving along a circular path with a constant speed of 10 ms^–1. What is the magnitude of the change in velocity of the particle, when it moves through an angle of 60^o around the centre of the circle?

zero

10 m/s

$$10\sqrt 2 m/s$$

$$10\sqrt 3 m/s$$

JEE Main 2019 (Online) 11th January Morning Slot

MCQ (Single Correct Answer)

-1

A slab is subjected to two forces $$\overrightarrow {{F_1}} $$ and $$\overrightarrow {{F_2}} $$ of same magnitude F as shown in the figure. Force $$\overrightarrow {{F_2}} $$ is in XY-plane while force $$\overrightarrow {{F_1}} $$ acts along z = axis at the point $$\left( {2\overrightarrow i + 3\overrightarrow j } \right).$$. The moment of these forces about point O will be :

JEE Main 2019 (Online) 11th January Morning Slot Physics - Rotational Motion Question 125 English

JEE Main 2019 (Online) 11th January Morning Slot Physics - Rotational Motion Question 125 English

$$\left( {3\widehat i - 2\widehat j - 3\widehat k} \right)F$$

$$\left( {3\widehat i + 2\widehat j - 3\widehat k} \right)F$$

$$\left( {3\widehat i + 2\widehat j + 3\widehat k} \right)F$$

$$\left( {3\widehat i - 2\widehat j + 3\widehat k} \right)F$$

JEE Main 2019 (Online) 11th January Morning Slot

MCQ (Single Correct Answer)

-1

An equilateral triangle ABC is cut from a thin solid sheet of wood. (see figure) D, E and F are the mid-points of its sides as shown and G is the centre of the triangle. The moment of inertia of the triangle about an axis passing through G and perpendicular to the plane of the triangle is I0. If the smaller triangle DEF is removed from ABC, the moment of inertia of the remaining figure about the same axis is I. then :

JEE Main 2019 (Online) 11th January Morning Slot Physics - Rotational Motion Question 124 English

JEE Main 2019 (Online) 11th January Morning Slot Physics - Rotational Motion Question 124 English

$${\rm I} = {{{{\rm I}_0}} \over 4}$$

$${\rm I} = {{15} \over {16}}{{\rm I}_0}$$

$${\rm I} = {9 \over {16}}{{\rm I}_0}$$

$${\rm I} = {3 \over 4}{{\rm I}_0}$$

JEE Main 2019 (Online) 10th January Evening Slot

MCQ (Single Correct Answer)

-1

Two identical spherical balls of mass M and radius R each are stuck on two ends of a rod of length 2R and mass M (see figure). The moment of inertia of the system about the axis passing perpendicularly through the centre of the rod is :

JEE Main 2019 (Online) 10th January Evening Slot Physics - Rotational Motion Question 127 English