JEE Main 2024 (Online) 1st February Morning Shift | Circular Motion Question 6 | Physics

JEE Main 2024 (Online) 1st February Morning Shift

MCQ (Single Correct Answer)

-1

A particle moving in a circle of radius $\mathrm{R}$ with uniform speed takes time $\mathrm{T}$ to complete one revolution.

If this particle is projected with the same speed at an angle $\theta$ to the horizontal, the maximum height attained by it is equal to $4 R$. The angle of projection $\theta$ is then given by :

$\sin ^{-1}\left[\frac{2 \mathrm{gT}^2}{\pi^2 \mathrm{R}}\right]^{\frac{1}{2}}$

$\sin ^{-1}\left[\frac{\pi^2 \mathrm{R}}{2 \mathrm{gT}^2}\right]^{\frac{1}{2}}$

$\cos ^{-1}\left[\frac{\pi \mathrm{R}}{2 \mathrm{gT}^2}\right]^{\frac{1}{2}}$

$\cos ^{-1}\left[\frac{2 \mathrm{gT}^2}{\pi^2 \mathrm{R}}\right]^{\frac{1}{2}}$

JEE Main 2024 (Online) 31st January Morning Shift

MCQ (Single Correct Answer)

-1

A coin is placed on a disc. The coefficient of friction between the coin and the disc is $$\mu$$. If the distance of the coin from the center of the disc is $$r$$, the maximum angular velocity which can be given to the disc, so that the coin does not slip away, is :

$$\sqrt{\frac{r}{\mu g}}$$

$$\sqrt{\frac{\mu g}{r}}$$

$$\frac{\mu g}{r}$$

$$\frac{\mu}{\sqrt{r g}}$$

JEE Main 2024 (Online) 29th January Evening Shift

MCQ (Single Correct Answer)

-1

A stone of mass $$900 \mathrm{~g}$$ is tied to a string and moved in a vertical circle of radius $$1 \mathrm{~m}$$ making $$10 \mathrm{~rpm}$$. The tension in the string, when the stone is at the lowest point is (if $$\pi^2=9.8$$ and $$g=9.8 \mathrm{~m} / \mathrm{s}^2$$) :

17.8 N

97 N

9.8 N

8.82 N

JEE Main 2024 (Online) 29th January Morning Shift

MCQ (Single Correct Answer)

-1

If the radius of curvature of the path of two particles of same mass are in the ratio $$3: 4$$, then in order to have constant centripetal force, their velocities will be in the ratio of :

$$1: \sqrt{3}$$

$$2: \sqrt{3}$$

$$\sqrt{3}: 2$$

$$\sqrt{3}: 1$$

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