1
JEE Main 2022 (Online) 29th June Evening Shift
Numerical
+4
-1 The Vernier constant of Vernier callipers is 0.1 mm and it has zero error of ($$-$$0.05) cm. While measuring diameter of a sphere, the main scale reading is 1.7 cm and coinciding vernier division is 5. The corrected diameter will be _________ $$\times$$ 10$$-$$2 cm.

2
JEE Main 2022 (Online) 28th June Evening Shift
Numerical
+4
-1 A student in the laboratory measures thickness of a wire using screw gauge. The readings are 1.22 mm, 1.23 mm, 1.19 mm and 1.20 mm. The percentage error is $${x \over {121}}\%$$. The value of x is ____________.

3
JEE Main 2022 (Online) 26th June Evening Shift
Numerical
+4
-1 A travelling microscope is used to determine the refractive index of a glass slab. If 40 divisions are there in 1 cm on main scale and 50 Vernier scale divisions are equal to 49 main scale divisions, then least count of the travelling microscope is __________ $$\times$$ 10$$-$$6 m.

4
JEE Main 2022 (Online) 26th June Morning Shift
Numerical
+4
-1 In a vernier callipers, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with nineth main scale division. Then the value of vernier constant will be _________ $$\times$$ 10$$-$$2 mm.

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